Angle A of triangle ABC will be ...
∠A = θ₂ -θ₃ = 77° -26° = 51°
Angle B of triangle ABC will be ...
∠B = 180° -θ₂ -θ₁ = 180° -77° -44° = 59°
Then angle C will be ...
∠C = 180° -∠A -∠B = 180° -51° -59° = 70°
By the Law of Sines,
a/sin(∠A) = c/sin(∠C)
a = c×sin(∠A)/sin(∠C)
a = (57 yd)×sin(51°)/sin(70°) ≈ 47.14 yd
The distance from B to C is 47.14 yd.
Answer:
92.75 cm^2
Step-by-step explanation:
Area of triangle ADC
= (1/2)×4.5×12 = 27
Area of triangle ACB
=(1/2)×12×5 = 30
Find AB using pythagoras theorem on triangle ABC:
AB^2 = 5^2 + 12^2 = 25 + 144
AB^2 = 169
AB = 13cm
Area of triangle AGB
= (1/2)×13×5.5 = 35.75
Total area = sum of the areas of the 3 triangles found above
= 27 + 30 + 35.75 = 92.75 cm^2
Answer:
The average number of students in kindergarten classes is 21.
Step-by-step explanation:
To do this, just add them up and divide by the total number (which is 10).
Answer:
What is the question??
Step-by-step explanation:
Volume = area * height
330 in^3 = area * 3 in
(330 in^3)/(3 in) = area = 110 in^2
