<h3>Answer:</h3>
1.9
Step-by-step explanation:
<h3>The above is direct and inverse variation.</h3>
A = kB/C -----------(1)
A=12
B = 3
C= 2
substitute A, B and C into equation (1).
12 = K × 3/2
12 = 3k/2
12×2 = 3k
3K = 24
dividing bothsides by 3
3K/3 = 24/3
K = 8
substitute K = 8 into equation (1)
A = 8B /C --------------(2)
Equation (2) is the equation connecting
A,B and C.
Finding B when A = 10 and C = 1.5
10 = 8B / 1.5
10× 1.5 = 8B
15 = 8B
Dividing bothsides by 8 :
B = 15/8
B = 1.875
B = 1. 9 ( approximately)
The hundred thousand column is the 6th column so you look at the 5th number and round
9 rounds up to 0
but this also changes the 900000 to 1000000
so 992449 = 1000000 to nearest hundred thousand
Itś basically the same thing as a compare and contrast circle graph when they intersect with eachother
Answer:
(B) Subtract 3x from both sides of the equation, and then divide both sides by 2.
Can't read the second question fully.
(A) 0.53
Step-by-step explanation:
Number 1:
If we have the equation , our first goal is to get rid of the x term on one side.
To do this we can subtract 3x from both sides. This leaves our equation to . To find x, we want to divide both sides by 2 since 2x divided by 2 is just x. Our goal is to isolate x. This leaves .
<em>I couldn't read Number 2 fully - I'm sorry :c</em>
<em></em>
Number 3:
Given the equation , we want to isolate x on one side.
To do this, we first apply the distributive property to the left side.
Now subtract 0.6 from both sides:
And divide both sides by 3.
This rounds to 0.53.
Hope this helped!