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2 years ago

What is the distance between 178 and 313 on a number line?

Mathematics

2 answers:

Damm [24]2 years ago

4 0

Answer:

135 is the distance

Step-by-step explanation:

I subtracted the numbers.

I hope this helped and have a great day!

(please vote this brainliest)

Luba_88 [7]2 years ago

3 0

Answer:

135

Step-by-step explanation:

Take 313 and subtract 178 from it to get your answer.

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Is the given value a solution to the equation? 4(n) - 3 = -2(n) + 9 n=2

nlexa [21]

Answer:

Yes!

The solution to the equation is n = 2

Step-by-step explanation:

Given the equation

$4\left(n\right)-3=-2\left(n\right)+9$

remove the parentheses

$4n-3=-2n+9$

Add 3 to both sides

$4n-3+3=-2n+9+3$

Simplify

$4n=-2n+12$

Add 2n to both sides

$4n+2n=-2n+12+2n$

Simplify

$6n=12$

Divide both sides by 6

$\frac{6n}{6}=\frac{12}{6}$

Simplify

$n=2$

Therefore, the value of n = 2.

Hence,

Yes!

The solution to the equation is n = 2

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2 years ago

What are the common factors common factors of 60,36 and 48?

nikitadnepr [17]

The answer is 2×2×3

if needed to be multiplied together the answer is 12

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2 years ago

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Sedbober [7]

Answer:

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Step-by-step explanation:

7 0

2 years ago

If cos Θ = negative 4 over 7, what are the values of sin Θ and tan Θ? sin Θ = ±square root 33 over 7; tan Θ = ±square root 33 ov

Natali5045456 [20]

Answer:

Answer = Option A;

sinθ = ± $\frac{\sqrt{33} }{7}$

tanθ = ± $\frac{\sqrt{33} }{4}$

Step-by-step explanation:

cosθ = $-\frac{4}{7}$

Remove the negative sign and evaluate cosθ = 4/7

cosθ = adjacent/hypotenuse.

Please see attached image for the right-angle triangle representation.

Let opp = length of opposite side of the triangle.

Let adj = length of adjacent side of the triangle.

Let hyp = length of hypotenuse side of the triangle

Using Pythagoras theorem,

$hyp^{2}= opp^{2} +adj^{2} ;\\\\7^{2}= opp^{2}+ 4^{2};\\ \\opp^{2} =7^{2}- 4^{2} \\\\opp^{2} = 49-16\\\\opp^{2} = 33;$

Take the square root of both sides.

$\sqrt{opp^{2} } =$ ± $\sqrt{33}$

opp = ± $\sqrt{33}$

sinθ = opposite/hypotenuse

sinθ = ± $\frac{\sqrt{33} }{7}$

tanθ = opposite/adjacent

tanθ = ± $\frac{\sqrt{33} }{4}$

6 0

2 years ago

Photo attached please help

arsen [322]

Answer:

A, B, D, and i think F

Step-by-step explanation:

im not sure of F, though.

8 0

2 years ago