We will solve this question using the formula for the area of a sector of a circle. We know that the area, A, of a sector of a circle is given by:
Where is the angle subtended by the sector at the center of the circle. Also, we know that in our case, .
Now, we know that is just the area of the original circle in question here, which has been given to us a .
Thus, the required area of the sector in question here is:
Thus the area of a 60º sector of this circle is m^2.
Thus, the second option is the correct option.