9514 1404 393
Answer:
1. HA is equivalent to AAS when the triangle is a right triangle.
2. AM = BM, so the triangles are congruent by HL. CPCTC
3. The triangles are congruent by HL. CPCTC
Step-by-step explanation:
1. The acute angle of the triangle together with the right angle comprise two angles of the triangle. When two corresponding angles and a corresponding side (the side opposite the right angle) are congruent, the right triangles are congruent by the AAS theorem. (This can be referred to as the HA theorem.)
__
2. CM = DM; MA = MB; ∠A = ∠C = 90°, so all of the requirements for the HL theorem are met. ΔCMA ≅ ΔDMB, so AC ≅ BD by CPCTC.
__
3. TS = TV, TR = TR, ∠S = ∠V = 90°, so all requirements for the HL theorem are met. ΔTSR ≅ ΔTVR, so RS ≅ RV by CPCTC.
Answer:
<u>749</u>
Step-by-step explanation:
Break apart the equation:
(7 x 100) + (7 x 7)
7 x 100 = 700
7 x 7 =49
700 + 49 = 749
Hope this helps
100 because 99.9999 nearest to any number on there would be 100
Answer:
Step-by-step explanation:
Answer:
1. A 2.C
Step-by-step explanation:
