Ok so domain is all allowed numbers
look at deonomenator and don't allow any numbers that will make it zero
none
that means
domain=all real numbers
vertex
in form
y=a(x-h)^2+k
(h,k)=vertex
we have
y=-2(x+3)^2-1
h=-3
k=-1
vertex=(-3,-1)
range
the vertex opens down so max is y=-1
y≤-1
domain is all real
vertex is (-3,-1)
y≤-1
C
The answer is B. one hundred four and thirty two ten-thousandths
Answer:
Step-by-step explanation:
The equation of a straight line can be represented in the slope intercept form as
y = mx + c
Where
m represents the slope of the line
c represents the y intercept
The equation of the given line is
2x + 4y = 20
4y = - 2x + 20
Dividing through by 4, it becomes
y = - x/2 + 5
Comparing with the slope intercept form, slope = - 1/2
If two lines are parallel, it means that they have the same slope. Therefore, the slope of the line passing through (- 6, 3) is - 1/2
To determine the y intercept, we would substitute m = - 1/2, x = - 6 and y = 3 into y = mx + c. It becomes
3 = - 1/2 × - 6 + c
3 = 3 + c
c = 3 - 3 = 0
The equation becomes
y = - x/2
Se calcula que la aceleración es - 8,35 m/s.
<h3 /><h3>¿Qué es la aceleración?</h3>
Ahora sabemos lo siguiente de la pregunta;
Velocidad inicial (u) = 60 km/h o 16,7 m/s
Tiempo empleado (t) = 2 s
Dado que;
v = tu + en
v = 0 m/s porque el carro se detenía
tu = -en
a = -(u/t)
a= -1(6,7 m/s/2 s)
a =- 8,35 m/s
La aceleración es negativa porque la velocidad disminuye con el tiempo.
Obtenga más información sobre la aceleración: brainly.com/question/12550364
#SPJ1
Answer:
There is enough evidence to say that the true average heat output of persons with the syndrmoe differs from the true average heat output of non-sufferers.
Step-by-step explanation:
We have to perform a hypothesis test on the difference between means.
The null and alternative hypothesis are:
μ1: mean heat output for subjects with the syndrome.
μ2: mean heat output for non-sufferers.
We will use a significance level of 0.05.
The difference between sample means is:
The standard error is
The t-statistic is
The degrees of freedom are
The critical value for a left tailed test at a significance level of 0.05 and 16 degrees of freedom is t=-1.746.
The t-statistic is below the critical value, so it lies in the rejection region.
The null hypothesis is rejected.
There is enough evidence to say that the true average heat output of persons with the syndrmoe differs from the true average heat output of non-sufferers.
