Which of the following are not conditions for producing work?
2 answers:
Answer:
A and C
Explanation:
We know that
Work done,W=Fd
Where F=Applied force
d=Displacement of object
Momentum, p= mv
It is not necessary that momentum must be greater than force .If momentum is less than force then the work can be produced because work depend upon displacement and applied force.
If the value of theta is not equal to zero the work can be produced if theta is equal to 30 ,45 or 60 degree.
Therefore, it is not necessary that atleast part of the applies force must act along the same line object moves.
If force is greater than weight then, the work can be produced .
If force is less than the weight then, the work cannot be produced .
Hence, the force must be very large.
You might be interested in
Complete Question
Due to blurring caused by atmospheric distortion, the best resolution that can be obtained by a normal, earth-based, visible-light telescope is about 0.3 arcsecond (there are 60 arcminutes in a degree and 60 arcseconds in an arcminute).Using Rayleigh's criterion, calculate the diameter of an earth-based telescope that gives this resolution with 700 nm light
Answer:
The diameter is
Explanation:
From the question we are told that
The best resolution is
The wavelength is
Generally the
1 arcminute = > 60 arcseconds
=> x arcminute => 0.3 arcsecond
So
=>
Now
60 arcminutes => 1 degree
0.005 arcminutes = > z degrees
=>
=>
Converting to radian
Generally the resolution is mathematically represented as
=>
=>
=>