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Thepotemich [5.8K]

2 years ago

12

Express 68 rations in dekarations

1 answer:

rewona [7]2 years ago

6 0

You have to take note of the prefix because it gives you a hint of its value with respect to the base value. The base value is ratio. When the prefix is deka, that means that 1 ration is equal to 0.1 dekaration according to the metric system. The conversion is as follows:

68 rations * 0.1 dekarations/1 ration = 6.8 dekarations

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Answer:

It won't increase according to Boyle's law

Explanation:

Volume of a gas varies inversely as the pressure so as more fixed volume of gas is added to the chamber the pressure reduces

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1 year ago

Water at 288.7 k flows through a 15.24-cm. diameter horizontal pipe into a 190-l drum. determine the minimum time it will take t

nikdorinn [45]

The flow will be laminar if Reynold's number $N_{R}$ is less than 2000.

Use the Reynold's formula and rearrange to calculate velocity of water in the pipe.

$N_{R} = \frac{v D}{\nu}$

Where, $v$ is velocity of the fluid, $D$ is the diameter of pipe, and $\nu$ is the kinematic viscosity i.e. $1.12 \times 10^{-6} m^2/s$ for water at 288.7 K from Appendix.

So, velocity is:

$v = \frac{N_{R} \nu}{D}$

The flow rate <em>Q</em>:

$Q = vA=v\pi D^2/4=\frac{\frac{N_R \nu}{D} \pi D^2}{4} =[tex] t = \frac{V}{\frac{N_R \nu \pi D}{4}} = \frac{4V}{N_R \nu \pi D} =\frac{4 \times 190 L\frac{10^{-3} m^3}{L}}{2000 \times 1.12\times 10^{-6} m^2/s \pi 15.24 cm\frac{1 m}{100 cm}} = 2226.3 s \frac{1 min}{60 s}= 37.1 min$ [/tex]

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2 years ago

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Answer:

b.

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2 years ago

Read 2 more answers

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Montano1993 [528]

Answer:

a.52.9 km/h

b.90 km

Explanation:

We are given that

$v_1=89km/h$

$t_1=30min$

$v_2=100km/h$

$t_2=12min$

$v_3=40km/h$

$t_3=45 min$

Time spend on eating lunch and buying ga=15 min.

a.Total time=30+12+45+15=102 minute= $\frac{102}{60}=1.7 hour$

1 hour=60 minutes

Distance= $speed\times time$

$d_1=v_1\times t_1=80\times\frac{30}{60}=40km$

$d_2=100\times \frac{12}{60}=20 km$

$d_3=40\times \frac{45}{60}=30 km$

Total distance= $d_1+d_2+d_3=40+20+30=90km$

Average speed= $\frac{total\;speed}{total\;time}$

Using the formula

Average speed= $\frac{90}{1.7}=52.9Km/h$

b.Total distance between the initial and final city lies along the route=90 km

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2 years ago

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qaws [65]

Answer:

≅50°

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And since we're using Δx, V₀ should really be the initial velocity in the x-direction. So:

Δx=(V₀cosθ)t+at²/2

Now luckily we are given everything we need to solve (or you found the info before posting here):

Δx=760 m
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With that we can plug the values in to get:

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$cos\theta=\frac{760}{1183.2}$

$\theta=cos^{-1}(\frac{760}{1183.2})\approx50^{o}$

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2 years ago