Answer:
36.28 kg
Explanation:
Given data:
Gravitational potential energy of object = 800 J
Height from ground = 2.245 m
Mass of object = ?
Solution:
Formula:
P.E = mgh
g =acceleration due to gravity = 9.8 m/s²
by putting values,
800 J = m× 9.8 m/s² ×2.25 m
J = kgm²/s²
800 kgm²/s² = m× 22.05 m²/s²
m = 800 kgm²/s² /22.05 m²/s²
m = 36.28 kg
Gas. Molecules in gas are able to move and vibrate around each other more freely than the molecules in liquids and/or solids due to the great amount of space in between them. Hope this helps! :)
Answer:
The standard change in free energy for the reaction = - 437.5 kj/mole
Explanation:
The standard change in free energy for the reaction:
4 KClO₃ (s) → 3 KClO₄(s) + KCl(s)
Given that ΔGf(KClO3(s)) = -290.9 kJ/mol;
ΔGf(KClO4(s)) = -300.4 kJ/mol;
ΔGf(KCl(s)) = -409 kJ/mol
According to Hess's law
ΔGr (Free energy change of reaction)= ∑(Product free energy - reactant free energy)
⇒ ΔGr⁰ = {3 x (-300.4) + (-409)} - {3 x (- 290.9)}
= - 901.2 - 409 + 872.7
= - 437.5 kj/mole
Answer:
12.8 g of must be withdrawn from tank
Explanation:
Let's assume gas inside tank behaves ideally.
According to ideal gas equation-
where P is pressure of , V is volume of , n is number of moles of , R is gas constant and T is temperature in kelvin scale.
We can also write,
Here V, T and R are constants.
So, ratio will also be constant before and after removal of from tank
Hence,
Here, and
So,
So, moles of must be withdrawn = (0.66 - 0.26) mol = 0.40 mol
Molar mass of = 32 g/mol
So, mass of must be withdrawn =
Answer:
600K
Explanation:
PV=nRT
T=PV/nR
= 1.6atm* 15.0L/ 0.5mol*0.0821LatmK^-1mol^-1
=600K