For 12, you would do 90=4x+42, and 48=4x, and x=12
for 15, you would do 90=8x+66, and 24=8x, and x=3
for 18, you would do 90=3x+57, and 33=3x, and x=11
Answer:
B.) -4
Step-by-step explanation:
y=mx+b
b is equal to the y-intercept.
Answer: 24≤ a < 26
Step-by-step explanation:
The modal class interval is the class interval with the highest frequency, the highest frequency from the table is 8 , which belongs to the class interval 24≤ a < 26
Answer:
3125 cm
Step-by-step explanation:
The distance between two villages is 0.625 km. Find the length in centimetres between the two villages on a map with a scale of 1:5000.
We are given the scale of
1: 5000
This means
1 km = 5000 cm
Hence:
1 km = 5000cm
0.625 km = x cm
Cross Multiply
x cm = 0.625 × 5000 cm
x cm = 3125 cm
Therefore, the length in centimetres between the two villages is 3125cm
Answer:
Step-by-step explanation:
Find the sum of the first 42 terms of the following series, to the nearest integer.
2,7,12
Solution
The sum is given by
SUM_n=n/2*(a_1+a_n)
a_n=a_1+(n-1)d
a_1=2, n=42, d=5
The 42nd term is therefore given by
a_42=2+(42-1)5=207
SUM_42=42/2*(2+207)=21*209=4389
The sum of the first 42 terms of the series, therefore, is 4389
