Ask question

Ask question

All categories

2 years ago

6

Jana buys 2 bags of dog dood for her dog one bag weighs 39 pounds .The other weighs 15 pounds.How many pounds do both bags weigh

?Complete the explanation of how you might solve the problem.

2 answers:

Pachacha [2.7K]2 years ago

4 0

Answer: They both weighs 54 pounds.

Step-by-step explanation:

If there are two bags of dog food and one of them weighs 39 pounds and the other weighs 15 pounds and to find out how many pounds both bags weigh together add them together.

39 + 15 = 54 pounds

rosijanka [135]2 years ago

4 0

Answer:

54 pounds.

Step-by-step explanation:

39+15=54

You might be interested in

If the sum of the zereos of the quadratic polynomial is 3x^2-(3k-2)x-(k-6) is equal to the product of the zereos, then find k?

lys-0071 [83]

Answer:

2

Step-by-step explanation:

So I'm going to use vieta's formula.

Let u and v the zeros of the given quadratic in ax^2+bx+c form.

By vieta's formula:

1) u+v=-b/a

2) uv=c/a

We are also given not by the formula but by this problem:

3) u+v=uv

If we plug 1) and 2) into 3) we get:

-b/a=c/a

Multiply both sides by a:

-b=c

Here we have:

a=3

b=-(3k-2)

c=-(k-6)

So we are solving

-b=c for k:

3k-2=-(k-6)

Distribute:

3k-2=-k+6

Add k on both sides:

4k-2=6

Add 2 on both side:

4k=8

Divide both sides by 4:

k=2

Let's check:

$3x^2-(3k-2)x-(k-6) \text{ with }k=2$ :

$3x^2-(3\cdot 2-2)x-(2-6)$

$3x^2-4x+4$

I'm going to solve $3x^2-4x+4=0$ for x using the quadratic formula:

$\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\frac{4\pm \sqrt{(-4)^2-4(3)(4)}}{2(3)}$

$\frac{4\pm \sqrt{16-16(3)}}{6}$

$\frac{4\pm \sqrt{16}\sqrt{1-(3)}}{6}$

$\frac{4\pm 4\sqrt{-2}}{6}$

$\frac{2\pm 2\sqrt{-2}}{3}$

$\frac{2\pm 2i\sqrt{2}}{3}$

Let's see if uv=u+v holds.

$uv=\frac{2+2i\sqrt{2}}{3} \cdot \frac{2-2i\sqrt{2}}{3}$

Keep in mind you are multiplying conjugates:

$uv=\frac{1}{9}(4-4i^2(2))$

$uv=\frac{1}{9}(4+4(2))$

$uv=\frac{12}{9}=\frac{4}{3}$

Let's see what u+v is now:

$u+v=\frac{2+2i\sqrt{2}}{3}+\frac{2-2i\sqrt{2}}{3}$

$u+v=\frac{2}{3}+\frac{2}{3}=\frac{4}{3}$

We have confirmed uv=u+v for k=2.

4 0

2 years ago

Use determinants to find out if the matrix is invertible.

wariber [46]

Answer:

The matrix is not invertible.

Step-by-step explanation:

We are given the following matrix in the question:

$A =\left[\begin{array}{ccc}-5&0&1\\-1&3&2\\0&10&6\end{array}\right]$

Condition for invertible matrix:

A matrix is invertible if and only if the the determinant is non-zero.

We can find the determinant of the matrix as:

$|A| = -5[(3)(6)-(2)(10)]-0[(-1)(6)-(2)(0)] + 1[(-1)(10)-(3)(0)]\\|A| = -5(18-20)+(-10)\\|A| = 10-10\\|A| = 0$

Since the determinant of the given matrix is zero, the given matrix is not invertible.

5 0

2 years ago

A rectangle has a height of 3p2+1 and a width of p3+4 your answer should be a polynomial in standard form

drek231 [11]

Answer:

3p^5+p^3+12p^2+4

Step-by-step explanation:

5 0

2 years ago

a law firm charges $100 per hour plus a $300 origination fee for its services find a function notation

Kisachek [45]

F(t)= $100 x h + 300 A reasonable domain is (1,2,3) and the range is ($400,$500,$600)

5 0

2 years ago

You are planning on retiling your bathroom floor and buy 96 square feet of tile. If the length of the bathroom is

Rudik [331]

Answer:

8 feet

Step-by-step explanation:

Given that 96 sq. feet of tile is bought to retile the bathroom.

It means area of bathroom is 9 $3/2 x^2 = 96\\=> 3 x^2 = 96*2=192\\=> x^2 = 192/3 = 64\\=>\sqrt{x^2} = \sqrt{64} \\=> x = 8$ 6 sq. feet

Width of bathroom be x

Given that the length of the bathroom is one and a half times the width

Length of bathroom in term sod width = 1 1/2* x = 3/2 x

we know area of rectangle is given by length * width

therefore area of bathroom =( x* 3/2 x) = 3/2 x^2

Also area of bathroom is 86 sq. feet, therefore

$3/2 x^2 = 96\\=> 3 x^2 = 96*2=192\\=> x^2 = 192/3 = 64\\=>\sqrt{x^2} = \sqrt{64} \\=> x = 8$

Thus, width of bathroom is 8 feet.

4 0

2 years ago