3(25x^3-16)
Hope that is what you were looking for
Answer:
he sum of the measures of two complementary angles is 90 degrees
Step-by-step explanation:
we know that
If two angles are complementary, then their sum is equal to 90 degrees
In this problem we have that
m∠ABD and m∠DBC are complementary
so
m∠ABD + m∠DBC=90° -----> by complementary angles
and
(m∠ABD + m∠DBC)+m∠EBC=180° -----> by a linear pair
Find the measure of angle EBC
substitute the given values
(90°)+m∠EBC=180°
∠EBC=180°-90°=90°
Ok so to solve to first one u do this:
62.4 - 31.53, which gives u 30.87. and then u add 30.87 and 31.33, and u get 62.4
for the second one u do the same thing.
This gives you three simultaneous equations:
6 = a + c
7 = 4a + c
1 = c
<u>c = 1
</u><u /><u />
If c =1,
6 = a + 1
<u>a = 5
</u><u /><u />
This doesn't work in the second equation, so the quadratic that goes through these points is not in the form y = ax^2 + bx + c
Was there supposed to be a b in the equation?
Answer:
there's no graphed pictured. but slope is rise/ run so just count the boxes between the points on the line. Up and down is the numerator and sideways is the denominator. If its decreasing from left to right it's negative, and if it's increasing left to right then it's positive