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2 years ago

Choose "extinct" if the species is extinct and "endangered" if the species is endangered.

Physics

2 answers:

Dovator [93]2 years ago

8 0

Answer:

B.endangered

Explanation:

Choose "extinct" if the species is extinct and "endangered" if the species is endangered.

Sixty years ago, as few as 20 whooping cranes were left on earth. Now, thanks to conservation efforts, there are more than 300 whooping cranes in the wild.

A.extinct

B.endangered

if there are 20 whooping cranes sixty years ago, and then we have more than 300 today. then it means that the species are endangered

I will go with B

An extinct species no longer exist because there are no offsprings of the parent specie which can give birth to more subspecies .

species no longer exist anywhere on Earth, and once gone they are gone ... on International Trade In Endangered Species like Wild Fauna and Flora (CITES). .... in 1975; the species now numbers more than 1, 000 animals .... whooping cranes, this approach fails to protect most endangered species

Endangered means that the existence is threatened by some human activities, prevailing conditions in the environment or the host it feeds on to survive no longer exists within it reach, hence its survival is at stake

ohaa [14]2 years ago

7 0

The species is actually endangered and not extinct because there are only 20 species left. Extinct actually means that there would be no species left and so it an incorrect option. The correct option among all the options that are given in the question is the second option or option "B". I hope the answer has helped you.

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Two small spheres with mass 10 gm and charge q, are suspended from a point by threads of length L=0.22m. What is the charge on e

Nataliya [291]

Answer:

$q=1.95*10^{-7}C$

Explanation:

According to the free-body diagram of the system, we have:

$\sum F_y: Tcos(15^\circ)-mg=0(1)\\\sum F_x: Tsin(15^\circ)-F_e=0(2)$

So, we can solve for T from (1):

$T=\frac{mg}{cos(15^\circ)}(3)$

Replacing (3) in (2):

$(\frac{mg}{cos(15^\circ)})sin(15^\circ)=F_e$

The electric force ( $F_e$ ) is given by the Coulomb's law. Recall that the charge q is the same in both spheres:

$(\frac{mg}{cos(15^\circ)})sin(15^\circ)=\frac{kq^2}{r^2}(4)$

According to pythagoras theorem, the distance of separation (r) of the spheres are given by:

$sin(15^\circ)=\frac{\frac{r}{2}}{L}\\r=2Lsin(15^\circ)(5)$

Finally, we replace (5) in (4) and solving for q:

$mgtan(15^\circ)=\frac{kq^2}{(2Lsin(15^\circ))^2}\\q=\sqrt{\frac{mgtan(15^\circ)(2Lsin(15^\circ))^2}{k}}\\q=\sqrt{\frac{10*10^{-3}kg(9.8\frac{m}{s^2})tan(15^\circ)(2(0.22m)sin(15^\circ))^2}{8.98*10^{9}\frac{N\cdot m^2}{C^2}}}\\q=1.95*10^{-7}C$

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2 years ago

A truck moves 70 m east, then moves 120 m west, and finally moves east again a distance of 90 m. If east is chosen as the positi

asambeis [7]

Answer:

140m east

Explanation:

If East is positive then lets rephrase the problem into integers

A truck moves +70 m, then moves -120m, and finally moves +90m.

So totally Displacement = +70-120+90= +140m

Since east is positive, the trucks resultant displacement is 140 m east of origin

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2 years ago

Collar P slides outward at a constant relative speed along rod AB, which rotates counterclockwise with a constant angular veloci

diamong [38]

Answer:

a= 23.65 ft/s²

Explanation:

given

r= 14.34m

ω=3.65rad/s

Ф=Ф₀ + ωt

t = Ф - Ф₀/ω

= (98-0)× $\frac{\pi}{180}$ /3.65

98°= 1.71042 rad

1.7104/3.65

t= 0.47 s

r₁(not given)

assuming r₁ =20 in

r₁ = r₀ + ut(uniform motion)

u = r₁ - r₀/t

r₀ = 14.34 in= 1.195 ft

r₁ = 20 in = 1.67 ft

= (1.667 - 1.195)/0.47

0.472/0.47

u= 1.00ft/s

acceleration at collar p

a=rω²

= 1.67 × 3.65²

a = 22.25ft/s²

acceleration of collar p related to the rod = 0

coriolis acceleration = 2ωu

= 2× 3.65×1 = 7.3 ft/s²

acceleration of collar p

= 22.5j + 0 + 7.3i

√(22.5² + 7.3²)

the magnitude of the acceleration of the collar P just as it reaches B in ft/s²

a= 23.65 ft/s²

4 0

2 years ago

A fighter plane is flying overhead at mach 1.50. What angle does the wave front of the shock wave produced make relative to the

olga2289 [7]

Answer:

θ = 41.80°

Explanation:

Given that

Mach number M= 1.5

We know that

M = u/c

Where c is the velocity of sound and u is the speed of plane

c= 340 m/s

u = 1.5 x 340 m/s

u = 510 m/s

We know that

$sin\theta =\dfrac{c}{u}$

Now by putting the values

$sin\theta =\dfrac{c}{u}$

$sin\theta =\dfrac{340}{510}$

θ = 41.80°

So the angle will be 41.80°.

8 0

2 years ago