Most people use the decomposition method but i dont know how to do that so i use the Joes method a method similar to decomp. but easier. canadian way
Find gcf: None complet trinomial: 18n^2+57-10 find the product=10(18) =-180 find the sum =57 -3 and 60 goes into both meaning if you multiply 3 and60 you get -180 and if you add them you get 57.
so (n-3)(n+60) divide by a in this case it 18 so (n<u>-3</u>)(n+<u>60</u>) 18 18 do not divide. treat it like a fraction so you reduce it to lowest terms (n<u>-3</u>)(n<u>-3) </u> 18 10 <u /> at this point its reduced to lowest terms so now you take the deniminator and move it beside the "n"
=(18n-3)(10n-3)
therefore your answer is (18n-3)(10n-3) I hoped this helped :)