Answer:
Step-by-step explanation:
Answer:
and
Step-by-step explanation:
Given
Bisector: CD
of Line AB
Required
Apply Pythagoras Theorem
From the question, CD bisects AB and it bisects it at D.
The relationship between AB and CD is given by the attachment
Considering ACD
From the attachment, we have that:
By Pythagoras Theorem, we have
Considering CBD
From the attachment, we have that:
By Pythagoras Theorem, we have:
Answer:
All of them are irrational except √9 which is rational.
Step-by-step explanation:
√5= 2.2606797749(irrational)
√9=3(rational) this one is rational
√7=2.64575131106(irrational)
√3.31662479035(irrational)
hope it helps.
Answer:
B. 2/3
Step-by-step explanation:
To solve this we have to take into account this axioms:
- The total probability is always equal to 1.
- The probability of a randomly selected point being inside the circle is equal to one minus the probability of being outside the circle.
Then, if the probabilities are proportional to the area, we have 1/3 probability of selecting a point inside a circle and (1-1/3)=2/3 probability of selecting a point that is outside the circle.
Then, the probabilty that a random selected point inside the square (the total probability space) and outside the circle is 2/3.
<em>so</em><em> </em><em>the</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>of</em><em> </em><em>option</em><em> </em><em>C</em><em>.</em>
<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em>⤴</em>
<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em><em>:</em><em>)</em>