1. Use a computer to randomly select 30 student IDs from all her students2. If the ice cream store owner asks 2300 people, will most likely pick cheesecake to be the flavor of the month.3. I would need the line plot4. I would need the graph to solve5. I would need the graph to solveClick to let others know, how helpful is it
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Answer:
Option c.
No damping
Step-by-step explanation:
We can easily solve this question by using a graphing calculator or any plotting tool.
The function is
f(x) = (√11)*cos(3.7x)
Which can be seen in the picture below
We can notice that f(x) is a cosine with maximum amplitude of (√11). Neither this factor nor the multiplication of x by 3.7 serve as a damping factor since they are constants.
f(x) does not present any dampening
Answer:
The value of x = 513
Step-by-step explanation:
Let x, y, and z be the three numbers
Given
Assuming x be the number which is 50% more than the sum of the other two numbers.
i.e.
(150)% of (y+z) = 1.5(y+z)
y + z = x/1.5
As we know that
substituting y + z = x / 1.5 in the equation
Multiply both sides by 1.5
Divide both sides by 2.5
Therefore, the value of x = 513
Ok so this is the first page
1.
78 pizzas. 20% of 65 is 13. Add that to 65 and you get 78 pizzas.
It is a 1.08% decrease. When you divide 65/60 you get 1.08. Im not 100% sure about this one
2.
Online store=$208 and the superstore=$224
The difference is $16 so it would be cheaper to get it at the online store
3.
It is $4000. For the first year you would multiply $20,000 by 5% which is 20000*.05=1000. Then multiply 1000 by 4 years to get $4,000
Instead of multiplying the 1000 by 4, multiply by 2 to get 2000. Subtract 4000-2000 to get 2000. You saved $2,000
Answer:
a) P(E|F) = 0.5
b) P(F|E) = 0.167
c) P(E|F') = 0.625
d) P(E′|F′) = 0.375
Step-by-step explanation:
P(E) = 0.6
P(F) = 0.2
P(E n F) = 0.1
a) P(E|F) = Probability of E occurring, given F has already occurred. It is given mathematically as
P(E|F) = [P(E n F)]/P(F) = 0.1/0.2 = 0.5
b) P(F|E) = Probability of F occurring, given E has already occurred. It is given mathematically as
P(F|E) = [P(E n F)]/P(E) = 0.1/0.6 = 0.167
c) P(E|F′) = Probability of E occurring, given F did not occur. It is given mathematically as
P(E|F') = [P(E n F')]/P(F')
But P(F') = 1 - P(F) = 1 - 0.2 = 0.8
P(E n F') = P(E) - P(E n F) = 0.6 - 0.1 = 0.5
P(E|F') = 0.5/0.8 = 0.625
d) P(E′|F′) = [P(E' n F')]/P(F')
P(F') = 0.8, P(Universal set) = P(U) = 1
P(E' n F') = P(U) - [P(E n F') + P(E' n F) + P(E n F) = 1 - (0.5 + 0.1 + 0.1) = 0.3
P(E′|F′) = 0.3/0.8 = 0.375