Ten times two is equal to twenty.
The product is negative 81 t squared + 16 ⇒ 2nd answer
Step-by-step explanation:
The product of two binomials (ax + b)(cx + d), where a, b, c, and d are constant
- Multiply (ax) by (cx) ⇒ 1st × 1st
- Multiply (ax) by (d) and (b) by (cx) ⇒ ext-reams and nears
- Add the two products ⇒ like terms
- Multiply (b) by (d) ⇒ 2nd × 2nd
Let us find the product of (9 t - 4) and (-9 t - 4)
Multiply the 1st two terms
∵ (9 t)(-9 t) = -81 t²
Multiply the ext-reams
∵ (9 t)(-4) = -36 t
Multiply the nears
∵ (-4)(-9 t) = 36 t
Add the like terms
∵ -36 t + 36 t = 0
Multiply the 2nd two terms
∵ (-4)(-4) = 16
Write the answer
∴ (9 t - 4)(-9 t - 4) = -81 t² + 0 + 16
∴ (9 t - 4)(-9 t - 4) = -81 t² + 16
The product is -81 t² + 16
Learn more:
You can learn more about the product of algebraic expressions in brainly.com/question/1617787
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(t^2+1)^100
USE CHAIN RULE
Outside first (using power rule)
100*(t^2+1)^99 * derivative of the inside
100(t^2+1)^99 * d(t^2+1)
100(t^2+1)^99 * 2t
200t(t^2+1)^99
2:7 = 4:14 because each is equal to 2/7. If you simplify 4:14 by dividing by 2, it simplifies to 2:7.
