Answer:
Explanation:
We will need a balanced chemical equation with masses and molar masses, so, let's gather all the information in one place.
MM: 63.55 107.87
Cu + 2AgNO₃ ⟶ Cu(NO₃)₂ + 2Ag
m/g: 100
(a) Moles of Cu
(b) Moles of Ag
(c) Mass of Ag
Answer:
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Answer:
The volume is 406 mL
Explanation:
Step 1: Data given
Molarity of a zinc nitrate solution = 1.3 M
Mass of zinc nitrate = 100 grams
Molar mass of Zn(NO3)2 = 189.36 g/mol
Step 2: Calculate moles Zn(NO3)2
Moles Zn(NO3)2 = mass Zn(NO3)2 / molar mass Zn(NO3)2
Moles Zn(NO3)2 = 100.0 grams / 189.36 g/mol
Moles Zn(NO3)2 = 0.5281 moles
Step 3: Calculate volume
Molarity = moles / volume
Volume = moles / molarity
Volume = 0.5281 moles / 1.3 M
Volume = 0.406 L = 406 mL
The volume is 406 mL
1.98 × 10^<span>-11</span><span> J i just took it this is the right awnser</span>
Krypton-84 is the most abundant type of Krypton. The answer is C.
If you need this to be explained, I will do my best it's a bit difficult to say how to find it out, but I will if you need me to.