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3 years ago

Which expression is equivalent to 7^3 ⋅ 7^−5? A.7^2 B.7^7 C.1 over 7 to the 2nd power D.1 over 7 to the 7th power

Mathematics

1 answer:

stepladder [879]3 years ago

4 0

$7^3\cdot7^{-5}=7^{-2}=\dfrac{1}{7^2}$

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Which of the following expressions are equivalent to -0.5(1.7+1.7)−0.5(1.7+1.7)minus, 0, point, 5, left parenthesis, 1, point, 7

Allisa [31]

The expressions equivalent to -0.5(1.7+1.7) are -0.5(1.7) - 0.5(1.7)

and 2(-0.5(1.7))

<h3>Distributive law of expansion</h3>

Given the expression below;

-0.5 (1.7 + 1.7)

According to the distributive law;

A(B+C) = AB + AC

Expand

-0.5(1.7) + (-0.5)(1.7)

-0.5(1.7) - 0.5(1.7)

2(-0.5(1.7))

Hence the expressions equivalent to -0.5(1.7+1.7) are -0.5(1.7) - 0.5(1.7)

and 2(-0.5(1.7))

Learn more on distributive law here: brainly.com/question/25224410

#SPJ1

7 0

1 year ago

(3p+5)(2) simplified

Vsevolod [243]

Multiply each term in the parentheses by 2
3p x 2 +5 x2

Calculate the product
6p+5 x 2

Multiple the number
6p x 10

That’s your answer
6p x 10

8 0

2 years ago

If the local linear approximation of f(x) = 2cos x + e^2x at x = 2 is used to find the approximation for f(2.1), then the % erro

yKpoI14uk [10]

<u>Answer-</u>

The % error of this approximation is 1.64%

<u>Solution-</u>

Here,

$\Rightarrow f(x) = 2\cos x + e^{2x}$

$\Rightarrow f'(x) = -2\sin x + 2e^{2x}$

And,

$\Rightarrow f(2) = 2\cos 2 + e^{4}$

$\Rightarrow f'(2) = -2\sin 2 + 2e^{4}$

Taking (2, f(2)) as a point and slope as, f'(2), the function would be,

$\Rightarrow y-y_1=m(x-x_1)$

$\Rightarrow y-(2\cos 2 + e^{4})=(-2\sin 2 + 2e^{4})(x-2)$

$\Rightarrow y=(-2\sin 2 + 2e^{4})(x-2)+(2\cos 2 + e^{4})$

The value of f(2.1) will be

$\Rightarrow y=(-2\sin 2 + 2e^{4})(2.1-2)+(2\cos 2 + e^{4})$

$\Rightarrow y=(-2\sin 2 + 2e^{4})(0.1)+(2\cos 2 + e^{4})$

$\Rightarrow y=64.5946$

According to given function, f(2.1) will be,

$\Rightarrow f(2.1) = 2\cos 2.1 + e^{2(2.1)}$

$\Rightarrow f(2.1) = 65.6766$

$\therefore \%\ error=\dfrac{65.6766-64.5946}{65.6766}=0.0164=1.64\%$

5 0

2 years ago

Which expression is equivalent to 5(4k+7)?<br><br> A. 5(7+4k)<br> B.7(5k+4)<br> C.35k+20<br> D.4k+35

Nata [24]

Answer:

A. 5(7+4k) = 35+ 20k

This is the same as 5(4k+7)

20k+35 is equal to 35+20k

5 0

2 years ago

What is the distance between points (3,2) and (6,4) to the nearest tenth?

vekshin1

Distance formula: √((y2-y1)^2+(x2-x1)^2)

Plug in the values √((4-2)^2+(6-3)^2)
√((2)^2+(3)^2) = √(4+9) = √13 = 3.6

3.6 is your answer.

4 0

2 years ago