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3 years ago

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A force of 1.35 newtons is required to accelerate a book by 1.5 meters/second2 along a frictionless surface. What is the mass of

the book?
A.
0.45 kilograms
B.
0.90 kilograms
C.
1.35 kilograms
D.
1.5 kilograms
E.
1.8 kilograms

2 answers:

marysya [2.9K]3 years ago

7 0

I believe D is the right answer

malfutka [58]3 years ago

3 0

B. seems like the answer, I'm not sure.

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A migrating robin flies due north with a speed of 12 m/s relative to the air. The air moves due east with a speed of 6.7 m/s rel

mafiozo [28]

Here it is given that speed of migrating Robin is 12 m/s relative to air

so we can say that

$\vec v_{ra} = 12 m/s$ North

so it will be

Let North direction is along Y axis and East direction is along X axis

$\vec v_{ra} = 12\hat j$

also it is given that speed of air is 6.7 m/s relative to ground

$\vec v_a = 6.7 \hat i$

now as we know by the concept of relative motion

$\vec v_{ab} = \vec v_a - \vec v_b$

$\vec v_{ra} = \vec v_r - \vec v_a$

now by rearranging the terms

$\vec v_r = \vec v_{ra} + \vec v_a$

$\vec v_r = 12 \hat j + 6.7 \hat i$

now we need to find the speed of Robin which means we need to find the magnitude of its velocity which we found above

So here we will say

$v_r = \sqrt{12^2 + 6.7^2}$

$v_r = 13.7 m/s$

so the net speed of Robin with respect to ground will be 13.7 m/s

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2 years ago

In an electric motor _____energy is transformed into_____energy?

irina1246 [14]

Answer:

mechanical energy

Explanation:

In an electric motor the electrical energy is converted into mechanical energy. Almost every mechanical movement that we see around us is accomplished by an electric motor. Electric machines are a means of converting energy. Motors take electrical energy and produce mechanical energy.

3 0

2 years ago

Xelga [282]

Answer:

About 7.67 m/s.

Explanation:

Mechanical energy is always conserved. Hence:

$\displaystyle \begin{aligned} E_i & = E_f \\ \\ U_i + K_i &= U_f + K_f\end{aligned}$

Where <em>U</em> is potential energy and <em>K</em> is kinetic energy.

Let the bottom of the slide be where potential energy equals zero. As a result, the final potential energy is zero. Additionally, because the child starts from rest, the initial kinetic energy is zero. Thus:

$\displaystyle U_i = K_f$

Substitute and solve for final velocity:
$\displaystyle \begin{aligned} mgh_i &= \frac{1}{2}mv_f^2 \\ \\ 2gh_i &= v^2_f \\ \\ v_f &= \sqrt{2gh_i} \\ \\ & =\sqrt{2(9.8\text{ m/s$^2$})(3.00\text{ m})} \\ \\ & \approx 7.67\text{ m/s} \end{aligned}$

In conclusion, the child's speed at the bottom of the slide is about 7.67 m/s.

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1 year ago

The pupil of your eye

Sav [38]

Answer:

What is the question?

Explanation:

If you tell me the question I can help.

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2 years ago

While traveling North along a highway a driver slows from 25 m/s to 15 m/s in 12 seconds. What is the

icang [17]

Answer:

- 0.8333 m/s^2

Explanation:

the equation for calculating acceleration that I have used is

(V2-V1)/t

where V2 is the final recorded velocity and V1 is the initial velocity and t is the duration of the acceleration.

which you plug the numbers in (15 - 25)/12 = 10/12 and because you are slowing down, it should be negative

I am in highschool honors physics so I am not college leveled, I might be wrong but I hope this is useful,

4 0

2 years ago