Answer:
92.87 g.
Explanation:
∵ The percentage yield = (actual yield/theoretical yield)*100.
- We need to calculate the theoretical yield:
From the balanced reaction:
<em>PCl₃ + Cl₂ → PCl₅,</em>
It is clear that 1 mol of PCl₃ reacts with 1 mol of Cl₂ to produce 1 mol of PCl₅.
- We need to calculate the no. of moles of 73.7 g PCl₃:
n = mass/molar mass = (73.7 g)/(137.33 g/mol) = 0.536 mol.
<u><em>Using cross multiplication:</em></u>
1 mol of PCl₃ produce → 1 mol of PCl₅, from stichiometry.
∴ 0.536 mol of PCl₃ produce → 0.536 mol of PCl₅.
∴ The mass of PCl₅ (theoretical yield) = (no. of moles) * (molar mass) = (0.536 mol)*(208.24 g/mol) = 111.62 g.
<em>∵ The percentage yield = (actual yield/theoretical yield)*100.</em>
The percentage yield = 83.2%, theoretical yield = 111.62 g.
∴ The actual yield of PCl₅ = (The percentage yield)(theoretical yield)/100 = (83.2%)(111.62 g)/100 = 92.87 g.
As a trend or pattern, the atomic radius decreases as you go left to right across the period, but increases as you go down a particular group.
To determine the strength of potassium permanganate with a standard solution of oxalic acid.
A. Phase changing. When phase changes nothing chemically changes about the substance, its still the same thing.
Answer:
2 CH2 + 3 O2 = 2 CO2 + 2 H2O
Explanation:
This is what I think that you meant by the question listed. When balancing a chemical equation, you want to make sure that there are equal amounts of each element on each side.
Originally, the equation's elements looked like this: 1 C on left & 1 C on right; 2 H on left & 2 H on right; 2 O on left and 3 O on right. Because these are not balanced, you need to add coefficients.
When adding coefficients, you need to make sure that all of the elements stay balanced, not just one that you are trying to fix. I know that some equations are really difficult to balance, and when that is the case, there are equation balancing websites that can help out.
However, what always helps me is making a chart and continuing to keep up with the changes I am making. It is a trial and error process.
