Answer:
Obtuse
Step-by-step explanation:
plzzz give brainliest
Divide 50 by 22: 2.27272727...
Round up to hundredth and your final answer is 2.27
hope that helps :)
Steps
I’m using elimination so I’m trying to get rid of y
To do that I multiply the first equation by 2 and the second by -3. Then solve
4x + 6x = 12
15x + -6x = -12
—————————
19x + 0 = 0
Divid by 19 to get x to one side. 0/19 is 0 so
X= 0
Plug that into an equation so 0 + 3y = 6
Divid by 3 and y = 2
Answer x = 0 y = 2
Answer:
11
26
44
Step-by-step explanation:
Answer:
The weight of the water in the pool is approximately 60,000 lb·f
Step-by-step explanation:
The details of the swimming pool are;
The dimensions of the rectangular cross-section of the swimming pool = 10 feet × 20 feet
The depth of the pool = 5 feet
The density of the water in the pool = 60 pounds per cubic foot
From the question, we have;
The weight of the water in Pound force = W = The volume of water in the pool given in ft.³ × The density of water in the pool given in lb/ft.³ × Acceleration due to gravity, g
The volume of water in the pool = Cross-sectional area × Depth
∴ The volume of water in the pool = 10 ft. × 20 ft. × 5 ft. = 1,000 ft.³
Acceleration due to gravity, g ≈ 32.09 ft./s²
∴ W = 1,000 ft.³ × 60 lb/ft.³ × 32.09 ft./s² = 266,196.089 N
266,196.089 N ≈ 60,000 lb·f
The weight of the water in the pool ≈ 60,000 lb·f
