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2 years ago

HELP ME PLEASE PLEASE IM BEGGING

Mathematics

1 answer:

Llana [10]2 years ago

5 0

Answer:

Consistent and independent

Step-by-step explanation:

This is bcoz dependent lines overlap each other, where as inconsistent lines dont intersect

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14 more than 6 times a number is greater than or equal to 28

Studentka2010 [4]

Answer:

6x + 14 ≥ 28

Step-by-step explanation:

6 times a number (6x)

14 more than (so, add 14 to 6x)

greater than or equal to, so this symbol ≥

= 6x + 14 ≥ 28

SOLVED:

6x≥14

x≥2.333333333333333

4 0

2 years ago

Expand the following. (3x + 2)2 A.9x2+6x+4 B.9x2+4 C.3x2+4 E.9x2+12x+4

PolarNik [594]

Step-by-step explanation:

working ;

(3x+2)^2

*Apply Perfect Square Formula : (a+b) =a^2+2ab+b^2

a = 3x,b = 2

(3x)^2 + 3x.2+2^2

finally Answer is:

= 9x^2 + 12x +4

5 0

2 years ago

Solve: 1 - 2k += = -3k

MariettaO [177]

Answer:

-1

Step-by-step explanation:

1-2k=-3k

1-2k+2k=-3k+2k

1=-1k

1/-1=-1k/-1

-1=k

3 0

2 years ago

Read 2 more answers

-5(c-2)=20-5c+10 help please

Rudiy27

Answer:

10 is the answer

Step-by-step explanation:

C(5,2) = 5! / 2! (5-2)!

C(5,2) = 5! / 2!3!

C(5,2) = 120/12

C(5,2) = 10

6 0

2 years ago

Read 2 more answers

Consider the differential equation y'' − y' − 30y = 0. Verify that the functions e−5x and e6x form a fundamental set of solution

Alex Ar [27]

Answer:

Step-by-step explanation:

We have to take the derivatives for both functions and replace in the differential equation. Hence

for y=e^{-5x}:

$y(x)=e^{-5x}\\y'(x)=-5e^{-5x}\\y''(x)=25e^{-5x}\\$

for y=e^{6x}:

$y(x)=e^{6x}\\y'(x)=6e^{6x}\\y''(x)=36e^{6x}\\$

Now we replace in the differential equation y'' − y' − 30y = 0

for y=e^{-5x}:

$25e^{-5x}+5e^{-5x}-30e^{-5x}=0\\25+5-30=0$

for y=e^{6x}:

$36e^{6x}-6e^{6x}-30=0\\36-6+30=0$

Now, to know if both function are linearly independent we calculate the Wronskian

$W(f,g)=fg'-f'g$

$W(e^{-5x},e^{6x})=(e^{-5x})(6e^{6x})-(-5e^{-5x})(e^{6x})\neq 0$

I hope this is useful for you

Best regard

7 0

2 years ago