2 years ago

Can you help me please it’s sue in like 5 min

Mathematics

1 answer:

Firlakuza [10]2 years ago

7 0

I’m like 90% sure it’s b

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In figure AB and CD bisect each other at O. State the 3 pairs of equal parts in ∆AOC and ∆BOD. Is ∆AOC ≅ ∆BOD? Give reasons

GuDViN [60]

Answer:

SEE EXPLANATION

Step-by-step explanation:

$In\:\triangle AOC \:\&\:\triangle BOD$

$AO \cong OB.... (given)$

$\angle AOC \cong\angle BOD$

$(vertical \: \angle s)$

$CO \cong OD.... (given)$

$\therefore \triangle AOC \:\cong\:\triangle BOD$

$(SAS \: postulate)$

So, the 3 pairs of equal parts in ∆AOC and ∆BOD are:

$AC = BD$

$m\angle OAC = m\angle OBD$

$m\angle OCA = m\angle ODB$

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2 years ago

In the triangle cosA/cosB= what can you help me?

ICE Princess25 [194]

The answer is 1.
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2 years ago

The sum of 3/4 and 18/19

SIZIF [17.4K]

The answer to this question is 2.

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2 years ago

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What is the density of an object having a mass of 25 g and a volume of 8.0 cm cubed

weqwewe [10]

Answer:

3.125 g/cm³.

Step-by-step explanation:

The formula for density/mass/volume is d = m/v, where d is density in grams per cm cubed, m is in grams, and v is in cm cubed.

In this case, m = 25 and v = 8.0.

d = 25 / 8.0

d = 25 / 8

d = 3.125.

So, the density of the object is 3.125 g/cm cubed.

Hope this helps!

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2 years ago

The boundary of a park is shaped like a circle. The park has a rectangular playground in the center and 2 square flower beds, on

fiasKO [112]

Answer:

Step-by-step explanation:

Get the perimeter of the each shape and add it all up to get the total fencing material required.

2 square flower beds = 2 x 4a = 8a

1 rectangular play ground = 2l + 2w

total fencing material = 8a + 2l + 2w

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2 years ago