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2 years ago

Geometry end of year review escape room: room H

Mathematics

1 answer:

denpristay [2]2 years ago

3 0

Answer:

1) D

2) A

3) C

4) B

5) B

6) C

Step-by-step explanation:

1) V = Bh

V = πr² (h)

V = π (7²)(5)

V = 49π (5)

V = 245π

V ≈ 769.3

2) V = 1/3 Bh

V = 1/3 (12*12)(9)

V = 1/3 (144)(9)

V = 1/3 (1296)

V = 432

3) V = 4/3πr³

V = 4/3 π (4.5³)

V = 4/3 π (91.125)

V = 121.5π

V ≈ 381.51

4) 3 pairs of rectangles

2(16)(5) = 2(80) = 160

2(16)(11) = 2(176) = 352

2(11)(5) = 2(55) = 110

Add together 160 + 352 + 110

622

5) Two triangles 3 rectangles

<em>Triangle</em>

2(1/2)(18)(5) = 18*5 = 90

<em>Rectangles</em>

18*7 = 126

5*7 = 35

18.7*7 = 130.9

Add together 90 + 126 + 35 + 130.9 = 381.9

C) SA = πr² + πrl --> l is the slant height

SA = π (8²) + π (8)(17)

SA = 64π + 136π

SA = 200π

SA ≈ 628

DACBBC

Starting with 60, divide by 5 --> 12

add by 13 --> 25

multiply by 3 --> 75

subtract by 11 --> 64

cube root 64 --> 4

Multiply 60 --> 240

CODE: 240

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Gwar [14]

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y = 2x + 1 is a linear equation:

When x increases, y increases twice as fast, so we need 2x
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2 years ago

Read 2 more answers

The table shows the number of books donated to a library each month. Suppose the growth continues exponentially.

telo118 [61]

$\bf \begin{array}{ccll}
\stackrel{t}{months}&\stackrel{A}{books}\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
0&80\\
1&100\\
2&125
\end{array}$ , we know that on Month 0, the Books were 80

$\bf \qquad \textit{Amount for Exponential Growth}\\\\
A=I(1 + r)^t\qquad 
\begin{cases}
A=\textit{accumulated amount}\to &80\\
I=\textit{initial amount}\\
r=rate\to r\%\to \frac{r}{100}\\
t=\textit{elapsed time}\to &0\\
\end{cases}
\\\\\\
80=I(1+r)^0\implies 80=I\qquad therefore\qquad \boxed{A=80(1+r)^t}$

we also know that on the first month there were 100 books,

$\bf \qquad \textit{Amount for Exponential Growth}\\\\
A=I(1 + r)^t\qquad 
\begin{cases}
A=\textit{accumulated amount}\to &100\\
I=\textit{initial amount}\\
r=rate\to r\%\to \frac{r}{100}\\
t=\textit{elapsed time}\to &1\\
\end{cases}
\\\\\\
100=80(1+r)^1\implies \cfrac{100}{80}=1+r\implies \cfrac{5}{4}=1+r
\implies 
\cfrac{5}{4}-1=r
\\\\\\
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now, how many books when t = 8? A=80(1+0.25)⁸, or A=80(1.25)⁸.

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2 years ago

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How many times does seven go into three hundred ninety four

Nookie1986 [14]

Answer: 56 times.

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394/7 = 56.3

56 * 7 = 392

392 + 7 = 399

399 is more than 394, therefore the answer is 56.

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