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2 years ago

Can someonehelp me again lol

Mathematics

2 answers:

Nezavi [6.7K]2 years ago

5 0

Answer:

The answer is A and B.

Step-by-step explanation:

insens350 [35]2 years ago

3 0

54 and 89 are correct answers.
Hope this helps!

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artcher [175]

Answer:

3,1

Step-by-step explanation:

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2 years ago

Someone please help me will give BRAILIEST!!!!!!

Misha Larkins [42]

The answer would be 1/5

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2 years ago

Please help!! I’ll mark the correct answer as brainly

GenaCL600 [577]

The answer is B. There can not be any alike "x" inputs.

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2 years ago

Read 2 more answers

A pen company averages 1.2 defective pens per carton produced (200 pens). The number of defects per carton is Poisson distribute

nlexa [21]

Answer:

a. P(x = 0 | λ = 1.2) = 0.301

b. P(x ≥ 8 | λ = 1.2) = 0.000

c. P(x > 5 | λ = 1.2) = 0.002

Step-by-step explanation:

If the number of defects per carton is Poisson distributed, with parameter 1.2 pens/carton, we can model the probability of k defects as:

$P(k)=\frac{\lambda^{k}e^{-\lambda}}{k!}= \frac{1.2^{k}\cdot e^{-1.2}}{k!}$

a. What is the probability of selecting a carton and finding no defective pens?

This happens for k=0, so the probability is:

$P(0)=\frac{1.2^{0}\cdot e^{-1.2}}{0!}=e^{-1.2}=0.301$

b. What is the probability of finding eight or more defective pens in a carton?

This can be calculated as one minus the probablity of having 7 or less defective pens.

$P(k\geq8)=1-P(k$

$P(0)=1.2^{0} \cdot e^{-1.2}/0!=1*0.3012/1=0.301\\\\P(1)=1.2^{1} \cdot e^{-1.2}/1!=1*0.3012/1=0.361\\\\P(2)=1.2^{2} \cdot e^{-1.2}/2!=1*0.3012/2=0.217\\\\P(3)=1.2^{3} \cdot e^{-1.2}/3!=2*0.3012/6=0.087\\\\P(4)=1.2^{4} \cdot e^{-1.2}/4!=2*0.3012/24=0.026\\\\P(5)=1.2^{5} \cdot e^{-1.2}/5!=2*0.3012/120=0.006\\\\P(6)=1.2^{6} \cdot e^{-1.2}/6!=3*0.3012/720=0.001\\\\P(7)=1.2^{7} \cdot e^{-1.2}/7!=4*0.3012/5040=0\\\\$

$P(k$

c. Suppose a purchaser of these pens will quit buying from the company if a carton contains more than five defective pens. What is the probability that a carton contains more than five defective pens?

We can calculate this as we did the previous question, but for k=5.

$P(k>5)=1-P(k\leq5)=1-\sum_{k=0}^5P(k)\\\\P(k>5)=1-(0.301+0.361+0.217+0.087+0.026+0.006)\\\\P(k>5)=1-0.998=0.002$

5 0

2 years ago

Can someone please help me on this question I will give brainliest

xz_007 [3.2K]

Answer:

A) 3 in

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Geometry

Surface Area of a Sphere: SA = 4πr²
Diameter: d = 2r

Step-by-step explanation:

Step 1: Define

SA = 23 in²

Step 2: Find r

Substitute [SAS]: 23 in² = 4πr²
Isolate r term: 23 in²/(4π) = r²
Isolate r: √[23 in²/(4π)] = r
Rewrite: r = √[23 in²/(4π)]
Evaluate: r = 1.35288 in

Step 3: Find d

Substitute [D]: d = 2(1.35288 in)
Multiply: d = 2.70576 in
Round: d ≈ 3 in

4 0

2 years ago