The period of the pendulum is given by the following equation
T = 2π * sqrt (L/g)
Where g is the gravity (free fall acceleration)
L is the longitude of the pendulum
T is the period.
We find g.............> (T /2π)^2 = L/g
g = L/(T /2π)^2...........> g = 22.657 m/s^2
Air, water , atomic acid , and pocket rocket
Answer:
The rod`s charge must be positive, because the gravity force is pointing downwards and the electrostatic force must be pointing upwards (in order to balance the gravity force)
The charge is q_2 = 1.667 times 10^(-7) C
Explanation:
F_e = F_g
where F_g = m g and F_e= (1/4 pi e_0)*(q_1*q_2)/d^2,
please see the file attached for more details.
Answer:
potential energy at origin is 
Explanation:
given data:
electric field E = 5*10^{6} N/C
at x = 43 cm, y = 28 cm
distance btween E and origin
potential energy per unit charge 
potential energy at origin is 2.57*10^{6} volt
