Answer:
where is the graph I can't see it how can I solve the problem if I don't see the graph can you show the graph please
It would be negative regardless of what you define as a positive direction.
Answer:
Cd(NO3)2 + Na2S --> CdS + 2 NaNO3
Explanation:
Answer:
v = 2.45 m/s
Explanation:
first we find the time taken during this motion by considering the vertical motion only and applying second equation of motion:
h = Vi t + (1/2)gt²
where,
h = height of cliff = 15 m
Vi = Initial Vertical Velocity = 0 m/s
t = time taken = ?
g = 9.8 m/s²
Therefore,
15 m = (0 m/s) t + (1/2)(9.8 m/s²)t²
t² = (15 m)/(4.9 m/s²)
t = √3.06 s²
t = 1.75 s
Now, we consider the horizontal motion. Since, we neglect air friction effects. Therefore, the horizontal motion has uniform velocity. Therefore,
s = vt
where,
s = horizontal distance covered = 4.3 m
v = original horizontal velocity = ?
Therefore,
4.3 m = v(1.75 s)
v = 4.3 m/1.75 s
<u>v = 2.45 m/s</u>
In #8, the distance and the (magnitude of displacement) are equal, because he crawled in a straight line.
Displacement = (straight-line distance from start-point to end-point) in the direction from start to end, regardless of what route was actually followed.
Displacement = 5m, in the negative direction.
In #9 . . . distance will be the same. Displacement is going to be the same magnitude, but in the positive direction.
This is so simple that it's hard to talk about.
In #8, "What was the bug's distance ?". "Distance was 5 meters.". "What was the bug's displacement ?", "Displacement was 5 meters backwards."
In #9, What was the bug's distance ?". "Distance was 5 meters.". "What was the bug's displacement ?", "Displacement was 5 meters forward."
