16 is the correct answer to this problem
If it there are two negative #'s you add them because they are on the same side of the number line.
Do you remember your unit circle? If sin ω = was -1/2, then it would be 7<span>π/6. If you're unfamiliar with the unit circle, we can derive it.
So, you know that sin is OPPOSITE/HYPOTENUSE, and it's in the third quadrant, where x and y would be negative. If sin </span>ω = -1/2, that means that ω = 1/sin*(-1/2), or sin^(-1)*(-1/2). Let's ignore the negative for now and plug sin^(-1)*(-1/2) into your calculator in radians. You get (1/6)π. But that's in Quadrant 1. We want it in Quadrant 3.
In one complete revolution, or 360°, there are 2π radians. That means, if you want to rotate it 180°, you need to add π to what you originally got.
π+(1/6)π=(7/6)π.
I highly recommend you memorize the unit circle if you haven't already, because you'll need it from Precalculus on.
Slope= 1
Y= 12
Equation= y = x + 12
(-8)^2
(-8)(-8)
64
Hope this helps!
