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2 years ago

Simplify m3 + m3 And Simplify 10+3c+5d-7c+d

Mathematics

1 answer:

Alex_Xolod [135]2 years ago

7 0

For this case we must simplify the following expressions:

$m ^ 3 + m ^ 3\\10 + 3c + 5d-7c + d$

Expression 1:

$m ^ 3 + m ^ 3 =$

They are similar terms so we can add.

$2m ^ 3$

Expression 2:

$10 + 3c + 5d-7c + d =$

We add similar terms taking into account that:

Equal signs are added and the same sign is placed.

Different signs are subtracted and the major sign is placed.

$10 + 3c-7c + 5d + d =\\10-4c + 6d$

Answer:

$m ^ 3 + m ^ 3 = 2m ^ 3\\10 + 3c + 5d-7c + d = 10-4c + 6d$

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Evaluate 5x²-3(x-2)+x for x=3

Zepler [3.9K]

Answer:

Step-by-step explanation:

Evaluate 5 x^2 - 3 (x - 2) + x where x = 3:

5 x^2 - 3 (x - 2) + x = 5×3^2 - 3 (3 - 2) + 3

3^2 = 9:

5×9 - 3 (3 - 2) + 3

3 - 2 = 1:

5×9 - 3 + 3

5×9 = 45:

45 - 3 + 3

45 + 3 = 48:

48 - 3

| 4 | 8

- | | 3

| 4 | 5:

Answer: 45

3 0

2 years ago

–3x – 3 < –63 This is rlly needed.

NISA [10]

-3x -3 < -63 subtract the 3 first
-3x < -60 then divide the -3 from both sides
x < 20 is your answer

6 0

2 years ago

Can someone help me find the equivalent expressions to the picture below? I’m having trouble

miss Akunina [59]

Answer:

Options (1), (2), (3) and (7)

Step-by-step explanation:

Given expression is $\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$ .

Now we will solve this expression with the help of law of exponents.

$\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}=\frac{\sqrt[3]{(2^3)^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{\sqrt[3]{2\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3\times 2^{\frac{1}{9}}}$

$=2^{\frac{1}{3}}\times 3^{\frac{1}{3}}\times 2^{-\frac{1}{9}}\times 3^{-1}$

$=2^{\frac{1}{3}-\frac{1}{9}}\times 3^{\frac{1}{3}-1}$

$=2^{\frac{3-1}{9}}\times 3^{\frac{1-3}{3}}$

$=2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }$ [Option 2]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$ [Option 1]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$

$=(2^2)^{\frac{1}{9}}\times (3^2)^{-\frac{1}{3} }$

$=\sqrt[9]{4}\times \sqrt[3]{\frac{1}{9} }$ [Option 3]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(2^2)^{\frac{1}{9}}\times (3^{-2})^{\frac{1}{3} }$

$=\sqrt[9]{2^2}\times \sqrt[3]{3^{-2}}$ [Option 7]

Therefore, Options (1), (2), (3) and (7) are the correct options.

6 0

2 years ago

Solve for g.<br> −3+5+6g=11−3g

Nataly_w [17]

Answer:

g = 1

Step-by-step explanation:

-3 + 5 + 6g = 11 - 3g

2 + 6g = 11 - 3g

Add 3g to both sides.

2 + 9g = 11

Subtract 2 from both sides

9g = 9

g = 1

5 0

2 years ago

What are the coordinates of the x-intercepts of the parabola y = x² - 8x + 15?

tamaranim1 [39]

Answer:

(3, 0) and (5, 0)

Step-by-step explanation:

we have

$y=x^{2}-8x+15$

we know that

The x-intercepts are the values of x when the value of y is equal to zero

For y=0

$x^{2}-8x+15=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2}-8x+15=0$

$a=1\\b=-8\\c=15$

substitute in the formula

$x=\frac{-(-8)\pm\sqrt{-8^{2}-4(1)(15)}} {2(1)}$

$x=\frac{8\pm\sqrt{4}} {2}$

$x=\frac{8\pm2} {2}$

$x=\frac{8+2} {2}=5$

$x=\frac{8-2} {2}=3$

x=3, x=5

therefore

The x-intercepts are (3,0) and (5,0)

4 0

2 years ago