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2 years ago

Greta answered 32 out of 40 questions correctly on a spelling test. what percentage of the words did she answer incorrectly?

Mathematics

1 answer:

vazorg [7]2 years ago

5 0

Answer:

20%

Step-by-step explanation:

If you divide 32 out of 40, you will get .8. Multiply that by 100 and you will get 80%. The question asks for the percentage of incorrect ones, so subtract 80 out of 100 and you will get 20%.

She got 20% of the words incorrect.

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2 years ago

Find the derivative.

Aleksandr [31]

Answer:

Using either method, we obtain: $t^\frac{3}{8}$

Step-by-step explanation:

a) By evaluating the integral:

$\frac{d}{dt} \int\limits^t_0 {\sqrt[8]{u^3} } \, du$

The integral itself can be evaluated by writing the root and exponent of the variable u as: $\sqrt[8]{u^3} =u^{\frac{3}{8}$

Then, an antiderivative of this is: $\frac{8}{11} u^\frac{3+8}{8} =\frac{8}{11} u^\frac{11}{8}$

which evaluated between the limits of integration gives:

$\frac{8}{11} t^\frac{11}{8}-\frac{8}{11} 0^\frac{11}{8}=\frac{8}{11} t^\frac{11}{8}$

and now the derivative of this expression with respect to "t" is:

$\frac{d}{dt} (\frac{8}{11} t^\frac{11}{8})=\frac{8}{11}\,*\,\frac{11}{8}\,t^\frac{3}{8}=t^\frac{3}{8}$

b) by differentiating the integral directly: We use Part 1 of the Fundamental Theorem of Calculus which states:

"If f is continuous on [a,b] then

$g(x)=\int\limits^x_a {f(t)} \, dt$

is continuous on [a,b], differentiable on (a,b) and $g'(x)=f(x)$

Since this this function $u^{\frac{3}{8}$ is continuous starting at zero, and differentiable on values larger than zero, then we can apply the theorem. That means:

$\frac{d}{dt} \int\limits^t_0 {u^\frac{3}{8} } } \, du=t^\frac{3}{8}$

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2 years ago

What is the answer for number 10?

barxatty [35]

Answer is a to the question

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2 years ago

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George and carmen went on a bicycle trip. they took a bus to their starting piont, and then biked the rest. they traveled 275 ki

rodikova [14]

We need to do a system of equations here.

x + y = 275 (if you travel x km by bike and y km by bus, then you travel 275 km as given in the problem)
y = x + 55 (the problem stated that they were bussed (y) the amount they biked plus 55 more km (x + 55))

The second equation is already solved for y. So, we can plug it in to the first equation.

x + (x + 55) = 275
2x + 55 = 275 [combine x terms]
2x = 220 [subtract 55 from both sides]
x = 110 [divide by 2 to isolate x and solve for it]

Now we know that x is 110, the distance they traveled by bike.
And that's what we needed to answer the problem!

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2 years ago