Answer: It can't.
Explanation:
In most cases, the melting point alone will not enable you to identify a compound. Millions of solid organic compounds, and their melting points, are known. Perhaps 10,000 of these will have the same melting point as your unknown compound.
Hope this helps!
I'm actually not sure... but maybe this will help!
http://www.dummies.com/education/science/chemistry/how-to-identify-chiral-centers-in-a-molecule/
Answer:
E=hcλ or E=hν , where h is Planck's constant i.e, energy is directly proportional to frequency and inversely proportional to wavelength.
Answer:
The correct option is;
a) As a juvenile
Explanation:
An high school student who is charged with drunk driving will be tried as a juvenile in the juvenile court and are likely to receive more penalties than normally prescribed for a defendant charged with driving under the influence.
The penalties that could be faced includes
1) Having to spend time in a juvenile detention center
2) Be put on probation
3) Recommendation for drug and alcohol counseling
4) Driving license suspension for a duration from 90 days to up to 2 years
5) Having driving under the influence intervention program.
Answer:
The enthalpy of the nitrogen-nitrogen bond in N2H4 is 162.6 kJ
Explanation:
For the reaction: N2H4(g)+H2(g)→2NH3(g), the enthalpy change of reaction is
ΔH rxn = 2 ΔHºf NH3 - ΔHºf N2H4
but we also know that the ΔH rxn is calculated by accounting the sum of number of bonds formed and bonds broken as follows:
ΔH rxn = 6H (N-H) + 4 (N-H) + 2H (H-H)
where H is the bond enthalpy .When bonds are broken H is positive, and negative when formed, in the product there are 6 N-H bonds , and in the reactants 4 N-H and 1 H-H bonds).
Consulting an appropiate reference handbook or table the following values are used:
ΔHºf (NH3) = -46 kJ/mol
ΔHºf (N2H4) = 95.94 kJ/mol
(The enthalpy of fomation of hydrogen in its standard state is zero)
H (N-H) = 391 kJ
H (H-H) = 432 kJ
H (N-N) = ?
So plugging our values:
ΔH rxn = 2mol ( -46.0 kJ/mol) - 1mol(95.4 kJ/mol) = -187.40 kJ
-187.40 kJ = 6(-391 kJ) + 4 (391 kJ) + 432 + H(N-N)
-187.40 kJ = -350 kJ + H(N-N)
H(N-N) = 162.6 kJ