Consider two particles of equal masses attached to each other by a light straight spring write the lagrangian center of mass
1 answer:
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Answer:
Explanation:
Given the following data;
Mass of child = 23 kg
Mass of bike = 5.5 kg
Velocity = 4.5 m/s
Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.
Mathematically, momentum is given by the formula;
To find the momentum of each of them;
I. Momentum of the child
Momentum C = mass * velocity
Momentum C = 23 * 4.5
Momentum C = 103.5 Kgm/s
II. Momentum of the bike
Momentum B = mass * velocity
Momentum B = 5.5 * 4.5
Momentum B = 24.75 Kgm/s
Hence, we can deduce from the calculations that the momentum of the child is greater than that of the bike because of the higher mass possessed by the child.
Answer:
The maximum mass the bar can support without yielding = 32408.26 kg
Explanation:
Yield stress of the material () = 200 M Pa
Diameter of the bar = 4.5 cm = 45 mm
We know that yield stress of the bar is given by the formula
Yield Stress =
⇒ =
---------------- (1)
⇒ Area of the bar (A) = ×
⇒ A = ×
⇒ A = 1589.625
Put all the values in equation (1) we get
⇒ = 200 × 1589.625
⇒ = 317925 N
In this bar the is equal to the weight of the bar.
⇒ =
× g
Where is the maximum mass the bar can support.
⇒ =
Put all the values in the above formula we get
⇒ =
⇒ = 32408.26 Kg
There fore the maximum mass the bar can support without yielding = 32408.26 kg