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3 years ago

How is energy transferred throughout the roller coaster

Physics

2 answers:

Angelina_Jolie [31]3 years ago

5 0

Answer:

On a roller coaster, energy changes from potential to kinetic energy and back again many times over the course of a ride. Kinetic energy is energy that an object has as a result of its motion. ... Traditionally, the coaster cars are pulled up the first hill by a chain; as the cars climb, they gain potential energy.

Explanation:

solmaris [256]3 years ago

3 0

Answer:

On a roller coaster, energy changes from potential to kinetic and back again many times over and over the course of the ride. Kinetic energy is energy that an object has because of its motion. All moving objects possess kinetic energy, which is determined by the mass and speed of the object.

Explanation:

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In which situation will the friction between an object and the surface on which it is moving be decreased? a. the object is push

lawyer [7]

d. the surface on which the object is moving is made smoother

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b. the weight of the moving object is decreased

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2 years ago

8. A crate of bananas weighing 3000 N is shipped from South America to New York, where it

LiRa [457]

Answer:

Mechanical advantage = 15

Explanation:

Given the following data;

Output force = 3000N

Input force = 200N

To find the mechanical advantage;

Mechanical advantage = output force/input force

Substituting into the equation, we have

Mechanical advantage = 3000/200

Mechanical advantage = 15

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2 years ago

How efficient are the small and large scale solar-power systems used in individual homes and industrial settings? What is the en

Leviafan [203]

Answer:

$\color{Blue}\huge\boxed{Answer}$

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Explanation:

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2 years ago

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77julia77 [94]

Answer:

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Explanation:

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2 years ago

One billiard ball is shot east at 2.00 m/s. A second, identical billiard ball is shot west at 1.00 m/s. The balls have a glancin

dimulka [17.4K]

Answer:

Velocity is 1.73 m/s along 54.65° south of east.

Explanation:

Let unknown velocity be v, mass of billiard ball be m and east direction be positive x axis.

Here momentum is conserved.

Initial momentum = Final momentum

Initial momentum = m x 2i + m x (-1)i = m i

Final momentum = m x v + m x 1.41 j = mv + 1.41 m j

Comparing

mi = mv + 1.41 m j

v = i - 1.41 j

Magnitude of velocity

$v=\sqrt{1^2+(-1.41)^2}=1.73m/s$

Direction,

$\theta =tan^{-1}\left ( \frac{-1.41}{1}\right )=-54.65^0$

Velocity is 1.73 m/s along 54.65° south of east.

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2 years ago