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3 years ago

I need help with this one question 8r - 5q = 3 solve for q how do i go about this

Mathematics

1 answer:

KATRIN_1 [288]3 years ago

6 0

8r - 3 = 5q --> q = (8r - 3)/5

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I need help with 14 and 15

bekas [8.4K]

Answer:

14: 9 + 5 ℎ

15: − 1 6 + 9/ 9

Step-by-step explanation:

14 : ℎ ⋅ 5 + ( 9 )

5ℎ+ (9)

^^ Re-order terms so constants are on the left

5ℎ+ ⋅ 9 also 5 ℎ+9 then after this you would wanna re arange the terms so it would be 9 + 5 ℎ

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2 years ago

CAN SOMEBODY HELP ME WITH THIS PROBLEM PLZZZ

kvv77 [185]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Find sin(a+B)

diamong [38]

Answer:

Cos A=5/13

we have

Cos² A= $1-Sin ²A$

25/169=1-Sin²A

sin²A=1-25/169

sin²A=144/169

Sin A= $\sqrt{144/169}=12/13$

again

Tan B=4/3

P/b=4/3

p=4

b=3

h= $\sqrt{3²+4²}=5$

Now

Sin B=p/h=4/5

in IV quadrant sin angle is negative so

Sin B=-4/5

CosB=b/h=3/5

Now

Sin(A+B):sinAcosB+CosAsinB

now 

substitute value

Sin(A+B):12/13*3/5+5/13*(-4/5)=36/65-4/13

=16/65 is a required answer

6 0

2 years ago

(ax-b)(bx+a)=(bx^2+a)a make x subject of the formula

Dmitriy789 [7]

Answer:hehe

Step-by-step explanation:

7 0

2 years ago

Describe the graph of the equation y = 4. Is the equation a function? vertical line; yes horizontal line; no vertical line; no h

Alik [6]

Yes it is a function. It is a horizontal line.

Every point on this line is of the form (x,4) where x can be any number you want. The y coordinate is fixed at 4 and cannot change. Two points on this line are (0,4) and (1,4). The horizontal line goes through 4 on the vertical y axis.

Why is it a function? Because it is impossible to draw a vertical line through more than one point on the graph of y = 4. The graph passes the vertical line test. Put another way, for any x input, there is exactly one y output.

Side Note: y = 4 is the same as y = 0x+4. Note how its in the form y = mx+b
m = 0 is the slope
b = 4 is the y intercept

8 0

2 years ago