How many protons and electrons are present in a barium atom?

1 answer:

6 0

To solve this problem, we can look it up on the periodic table.

Barium has a mass number of 56, also the 56th element on the table. Mass number actually is equal to the number of protons, proton number of an element is like an ID card number, which no other elements have the same. So, the number of protons is 56.

Electrons of an atom equals to the number of proton too. So the number of electrons of barium atom is also 56. If the number of electrons is changed, the atom is no longer an atom, it'll become ions.

So yes, both answer is 56.

You might be interested in

5. The mass of cobalt-60 in a sample is found to have decreased from 0.800g to 0.200g in a

Ludmilka [50]

Answer:

5.25yr

Explanation:

I think so

6 0

2 years ago

Why are some fatty acids called saturated?

Len [333]

Fats (triglycerides) that contain palmitic acid and stearic acid are therefore known as saturated fats. Fats made up of saturated fatty acids are solid at room temperature. ... Because it is polyunsaturated, it is liquid at room temperature.

4 0

2 years ago

Good day please help me thank you

NARA [144]

I think c I’m not positive about the question but I think c

6 0

2 years ago

Read 2 more answers

Because water molecules are polar and carbon dioxide molecules are nonpolar,

Gala2k [10]

The correct is D.

Water is a polar molecule and it has polar bonds, which carry partially positive and partially negative charges. This polar bond increases the attraction between molecules of water and thus it requires a greater energy to break the bond between the molecules of water compare to carbon dioxide, which is a non polar molecule. Thus, water has a higher boiling point than carbon dioxide.

4 0

2 years ago

Read 2 more answers

A manganese electrode was oxidized electrically. If the mass of the electrode decreased by 225 mg during the passage of 1580 cou

qwelly [4]

Answer:

<u>Oxidation state of Mn = +4</u>

Explanation:

Atomic mass of Mn = 55g/mol

From Faraday's law of electrolysis,

Electrochemical equivalent = $\frac{mass}{charge}$