Hence the value of the expression above are as listed below
<em>f(6+4) = 25</em>
<em>f(6)+f(4) = 20</em>
<em>f(6-4) = 1</em>
<em>f(6)-f(4) = 6</em>
<em>f(6*4) = 67</em>
<em>f(6)*f(4) = 91</em>
<h3>Functions and values</h3>
Given the expression below f(x) = 3x - 5
f(6+4) = f(10) =3(10) - 5
f(6+4) = 25
f(6) = 3(6) - 5
f(6) = 18 - 5 = 13
f(4) = 3(4) - 5
f(4) = 7
f(6)+f(4) = 13+7
f(6)+f(4) = 20
f(6-4) = f(2) =3(2) - 5
f(6-4) = 1
f(6) = 3(6) - 5
f(6) = 18 - 5 = 13
f(4) = 3(4) - 5
f(4) = 7
f(6)-f(4) = 13-7
f(6)-f(4) = 6
f(6*4) = f(24) =3(24) - 5
f(6*4) = 67
f(6) = 3(6) - 5
f(6) = 18 - 5 = 13
f(4) = 3(4) - 5
f(4) = 7
f(6)*f(4) = 13*7
f(6)*f(4) = 91
Learn more on function and values here: brainly.com/question/2284360
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Answer:I think it is C
Step-by-step explanation:I think it i C
Answer: 1 3/4(8)= 14
Step-by-step explanation:
That is the correct answer
In order to make a fraction as large as possible, you want the numerator to be large, and the denominator to be small.
Using the counting numbers, the smallest denominator (x - y) you can make is ' 1 '.
Now you just have to make the numerator large. You do that simply by using the largest two numbers you have available . . . 49 and 50 .
Now the fraction is (49 + 50) / 1 = 99 .
