2/3x - 1/2 = 1/3 + 5/6x....multiply the entire equation by the common denominator of 6...this will get rid of the fractions.

6(2/3x - 1/2) = 6(1/3 + 5/6x) =
4x - 3 = 2 + 5x...subtract 5x from both sides
4x - 5x - 3 = 2...add 3 to both sides
4x - 5x = 2 + 3...combine terms
-x = 5...multiply by -1 to make x positive
x = -5

7 0

3 years ago

Read 2 more answers

(-3)³ + (-4)² - (-2)³

AleksAgata [21]

Answer:

$=-3$

Step-by-step explanation:

$\left(-3\right)^3+\left(-4\right)^2-\left(-2\right)^3\\Follow\:the\:PEMDAS\:order\:of\:operations\\\mathrm{Calculate\:exponents}\:\left(-3\right)^3\::\quad -27\\\left(-3\right)^3\\\mathrm{Apply\:exponent\:rule}:\quad \left(-a\right)^n=-a^n,\:\mathrm{if\:}n\mathrm{\:is\:odd}\\\left(-3\right)^3=-3^3=-27\\=-27+\left(-4\right)^2-\left(-2\right)^3\\\mathrm{Calculate\:exponents}\:\left(-4\right)^2\::\quad 16\\\left(-4\right)^2$

$\mathrm{Apply\:exponent\:rule}:\quad \left(-a\right)^n=a^n,\:\mathrm{if\:}n\mathrm{\:is\:even}\\\left(-4\right)^2=4^2=16\\=-27+16-\left(-2\right)^3\\\mathrm{Calculate\:exponents}\:\left(-2\right)^3\::\quad -8\\\left(-2\right)^3\\\mathrm{Apply\:exponent\:rule}:\quad \left(-a\right)^n=-a^n,\:\mathrm{if\:}n\mathrm{\:is\:odd}\\\left(-2\right)^3=-2^3=-8\\=-27+16-\left(-8\right)\\\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:-27+16-\left(-8\right)\::\quad -3\\-27+16-\left(-8\right)$

$-27+16=-11\\=-11-\left(-8\right)\\\mathrm{Apply\:rule\:}-\left(-a\right)\:=\:+a\\-\left(-8\right)=+8\\=-11+8\\-11+8=-3\\=-3$

8 0

2 years ago

Read 2 more answers