2 Polnis
1 answer:
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Answer:
v = 7.67 m/s for L= 1m
Explanation:
Let's use the conservation of mechanical energy, at the highest point and the lowest point
Initial. Vertical ruler
Em₀ = mg h
Final. Just before touching the floor
= K = ½ I w²
Em₀ =
m g h = ½ I w²
The moment of inertia of a ruler that turns on one end is
I = 1/3 m L²
Let's replace
m g h = ½ (1/3 m L²) w²2
g h = 1/6 L² w²
They ask for the speed of the end so the height h is equal to the length of the ruler
g L = 1/6 L² w²
The linear and angular variables are related
v = w r
w = v / r
In this case the point of interest a in strangers r = L
g L = 1/6 L² v² / L²
v = √ 6 g L
Let's calculate
Assume that the length of the meter is L = 1 m
v = √ (6 9.8 1)
v = 7.67 m/s
The experiment's time period is unaffected by the change in amplitude in either experiment.
<h3>What are the variables that affect time in SHM?</h3>The time frame is provided by:
where,
T = Time period.
M = mass.
k = spring constant.
We can see from the formula above that the only factors affecting the time period in a Simple Harmonic Motion (SHM) are the object's mass and spring constant. Any changes in the object's mass or the spring constant will cause the time period to adapt.
<h3>Describe the Spring Constant.</h3>The attribute is known as a spring's "spring constant" describes the relationship between the force acting on a spring and the displacement it causes. In other terms, it describes the stiffness and size of a spring's range of motion.
To know more about Simple Harmonic Motion (SHM) visit:
#SPJ4