T1 + t2 = 2h and 30min;
t1 * 600 = t2 * 400 => t2 = (3/2) * t1;
then, t1 + (3/2) * t1 = 2h and 30min => 2t1 + 3t1 = 5h => 5*t1 = 5h => t1 = 1h => t2 = 1h and 30 min;
The distance is 2 * 1 * 600 = 1200miles;
Answer:
all numbers natural,integer,rational,real algebra comes under real numbers
except the equations with alphabets
By graph of object A the rate of change is estimated at 17/6.
Object B's rate of change is 10/3=20/6.
Comparing object A to object B:
17/6 <20/6
Object B is faster by:
17/6x=20/6
(6/17)(17/6)x=(20/6)(6/17)
x=20/17≈1.18
B)
Object B by a factor of 1.19
Since I made an estimation from graph of object A , my solution is off by. 01 but it is the closest I can get. The solution B is correct.
Answer:
106.81 mm
Step-by-step explanation:
C=2πr=2·π·17≈106.81415
