Question

analyze the results of a cross between two organisms that are both heterozygous for two different genes (AaBb) use a punnett square to evaluate the possible genotypes list all the genotypes form you punnett square in answer space determine how many phenotypes can be produced in the offspring determine the probability of producing offspring with the aabb genotype

Answer 1

The  cross  of  heterozygous  AaBb as  parental  phenotype led   to  formation  of  16  phenotype   of  the  offspring.This  is  because  this  is  dihybrid   form  of inheritance .The   probability  of  having  aabb   offspring  is  1/16  since   there  is  only  one  aabb  type  of  offspring  phenotype  out  of  the  16.  An  illustration  of  how  crossing  is  done  is  as  per  punnet square  below