Help please! Will mark you as Brainliest!

Just need help on first one.

Nataly [62]

Answer:

1st one because they make less than the actual house

7 0

2 years ago

Can someone help me please ?? :)

ki77a [65]

The answer would be 1/8 because when 1/8 is divide into the endpoints of AB you will recieve 1/8 of the endpoint numbers. Like 1/8 of 4 would be written as 1/8 times 4/1 since its a fraction multiply 1 times 4 and 8 times 1 to get 4/8. 4 goes into 4 one time and into 8 2 times giving you 1/2. Hope this helped. If you ever need help with math use this calculator and bookmark it so you can have it when you need it https://www.symbolab.com/

8 0

2 years ago

Read 2 more answers

Please help solve by elimination I hope its not blurry Have a nice day and Goodnight

strojnjashka [21]

Answer:

$\displaystyle \textcolor{black}{4.}\:[-3, -5]$

$\displaystyle \textcolor{black}{3.}\:[8, -1]$

$\displaystyle \textcolor{black}{2.}\:[4, -7]$

$\displaystyle \textcolor{black}{1.}\:[3, -2]$

Step-by-step explanation:

When using the Elimination method, you eradicate one pair of variables so they are set to zero. It does not matter which pair is selected:

$\displaystyle \left \{ {{2x - 3y = 9} \atop {-5x - 3y = 30}} \right.$

{2x - 3y = 9

{⅖[−5x - 3y = 30]

$\displaystyle \left \{ {{2x - 3y = 9} \atop {-2x - 1\frac{1}{5}y = 12}} \right. \\ \\ \frac{-4\frac{1}{5}y}{-4\frac{1}{5}} = \frac{21}{-4\frac{1}{5}} \\ \\ \boxed{y = -5, x = -3}$

------------------------------------------------------------------------------------------

$\displaystyle \left \{ {{x - 2y = 10} \atop {x + 3y = 5}} \right.$

{x - 2y = 10

{⅔[x + 3y = 5]

$\displaystyle \left \{ {{x - 2y = 10} \atop {\frac{2}{3}x + 2y = 3\frac{1}{3}}} \right. \\ \\ \frac{1\frac{2}{3}x}{1\frac{2}{3}} = \frac{13\frac{1}{3}}{1\frac{2}{3}} \\ \\ \boxed{x = 8, y = -1}$

_______________________________________________

$\displaystyle \left \{ {{y = -3x + 5} \atop {y = -8x + 25}} \right.$

{y = −3x + 5

{−⅜[y = −8x + 25]

$\displaystyle \left \{ {{y = -3x + 5} \atop {-\frac{3}{8}y = 3x - 9\frac{3}{8}}} \right. \\ \\ \frac{\frac{5}{8}y}{\frac{5}{8}} = \frac{-4\frac{3}{8}}{\frac{5}{8}} \\ \\ \boxed{y = -7, x = 4}$

------------------------------------------------------------------------------------------

$\displaystyle \left \{ {{y = -x + 1} \atop {y = 4x - 14}} \right.$

{y = −x + 1

{¼[y = 4x - 14]

$\displaystyle \left \{ {{y = -x + 1} \atop {\frac{1}{4}y = x - 3\frac{1}{2}}} \right. \\ \\ \frac{1\frac{1}{4}y}{1\frac{1}{4}} = \frac{-2\frac{1}{2}}{1\frac{1}{4}} \\ \\ \boxed{y = -2, x = 3}$