2x-4+4x-1=8x-43
-2x=-38
x=19
so QS=2(2*19-4)=68
It depends on what kind of problem it is
Answer:
mean = 1 power failure
variance = 1 (power failure)²
Step-by-step explanation:
Since the mean is computed as
mean = E(x) = ∑ x * p(x) for all x
then for the random variable x=power failures , we have
mean = ∑ x * p(x) = 0 * 0.4 + 1* 0.3 + 2*0.2 + 3* 0.1 = 1 power failure
since the variance can be calculated through
variance = ∑[x-E(x)]² * p(x) for all x
but easily in this way
variance = E(x²) - [E(x)]² , then
E(x²) = ∑ x² * p(x) = 0² * 0.4 + 1²* 0.3 + 2²*0.2 + 3²* 0.1 = 2 power failure²
then
variance = 2 power failure² - (1 power failure)² = 1 power failure²
therefore
mean = 1 power failure
variance = 1 power failure²
Answer:
Step-by-step explanation:
Assuming that the first exponent in the formula for the curve should be 3, not 2...
The derivative is
The slope of the tangent line at the point (-1, 2) is the value of the derivative at x = -1.
The slope of the normal line is the opposite reciprocal of the slope of the tangent line.
Using the Point-Slope form of a linear equation, the normal line is
