Answer:
3/4
Step-by-step explanation:
Q = 
{the smallest common multiple of 10, 4 and 5 is 5×2×2 = 20 (denominator)}
Q =
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We take the equation <span>d = -16t^2+12t</span> and subtract d from both sides to get
0<span> = -16t^2+12t - d
We apply the quadratic formula to solve for t. With a = -16, b = 12, c = -d, we have
t = [ -(12) </span><span>± √( 12^2 - 4(-16)(-d) ) ] / [2 * -16]</span>
= [- 12 ± √(144-64d) ] / (-32)
= [- 12 ± √16(9-4d)] / (-32)
= [- 12 ± 4√(9-4d)] / (-32)
= 3/8 ±√(9-4d) / 8
The answer to your question is t = 3/8 ±√(9-4d) / 8
A is 3
B she can pick 2 by 2
Answer - 11
I’m assuming you’re trying to find the line AB (basically the distance between point A and B). If that’s the case, since they both have the same x vale, subtract their y values. 14-3 gives you 11, which is the length of line AB
