Find a number that has four identical factors each factor must be greater than 1 and can have only 1 and itself as factors

1 answer:

7 0

"Have only 1 and itself as a factor" is definition of prime

so each factor must be prime

let ssay 2
2 is prime

2^4=16
a number is 16

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prisoha [69]

Answer:

No solution

Step-by-step explanation:

3 x + y = 4 (1)

− 3 x − y = − 8 (2)

Add (1) and (2)

0 + 0 = -4

0 = -4 is a false statement

So, no solution

5 0

2 years ago

Paraphin [41]

Answer:

17,12,15,14,12 answer 90

6 0

1 year ago

Svetradugi [14.3K]

For complex number, the magnitude is pretty straight forward:

sqrt(6^2 + 2^2) = sqrt(40)

For any a + bi, the magnitude will be sqrt(a^2 + b^2)

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2 years ago

Nookie1986 [14]

Answer:

Step-by-step explanation:

We can figure out the length of AB by using the distance formula.

$D = \sqrt{(7-4)^{2} + (-9-(-5))^{2} }\\ D = \sqrt{(3)^{2} + (-4)^{2} }\\D = \sqrt{9 + 16}\\D = \sqrt{25}\\D=5$

So the distance is 5

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2 years ago

777dan777 [17]

Answer:

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7 0

2 years ago