Are you doing FLVS? IF so I need hep
I think it would -2!! Sorry if I’m wrong
Answer:
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Step-by-step explanation:
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Answer:
these three apply:
ΔCBA ≈ ΔFED
ΔBAC ≈ ΔEDF
ΔABC ≈ ΔDEF
Step-by-step explanation:
Answer:
Step-by-step explanation:
The probability of getting one even and one odd is the sum of probability of getting even and of getting odd and even. Since there are 3 even or odd on each die out of six numbers you have
P(EO)(3/6)(3/6)=1/4 and P(OE)=(3/6)(3/6)=1/4 so 1/4+1/4= 1/2
or you can find the probability of getting two odds or two evens and subtract that from 1
P(EE)=(3/6)(3/6)=1/4, P(OO)=(3/6)(3/6)=1/4
P(EO)=1-1/4-1/4=1/2
