Answer:
Step-by-step explanation:
To find the center and the radius, we need to put the equation in the (x-a)^2+(y-b)^2=r^2 [a is the x-coordinate, b is the y-coordinate, and r is the radius].
(x+6)^2+(y+7)^2 - 36 - 49 + 69 = 0
(x+6)^2+(y+7)^2 - 16 = 0
(x+6)^2+(y+7)^2 = 16
(x+6)^2+(y+7)^2 = 4^2
The center is (-6,-7) and the radius is 4.
Hope this helps!
Answer:
Step-by-step explanation:
The straight line passes through (0,1) and (2,-2).
Equation of a straight line passing through two points (x1,y1) and (x2,y2)
is given by:
Everything to the left of the line is shaded.
We have to visualize the graph:the straight line has a positive y-intercept and a negative slope.The graph is given in the attachment below.
From the figure we can see origin lies on the shaded region.Hence (0,0) should satisfy the inequality.
LHS=y=0
RHS=
LHS<RHS as 0<1
Hence , the inequality is:
Answer:
Step-by-step explanation:
a) 3x^2-12x-11=3*x^2-3*2*2*x+3*4-23=3*(x^2-2*2x+2^2)-23=3*(x-2)^2-23
so a= -2 ,b= -23
b) x1=[12+V(12^2-4*3* -11)]/6=12/6+V(144+132)/6=2+2/6V69=2+1/3V69=
2+V69/9=2+V23/3
c=2, d= 23/3
air sacs or alveoli the lungs and blood 3 transport
of respiratory gases