Newton's Law of Cooling
Tf=Ts+(Ti-Ts)e^(-kt) where Tf is temp at time t, Ts is temp of surroundings, Ti is temp of object/fluid. So we need to find k first.
200=68+(210-68)e^(-10k)
132=142e^(-10k)
132/142=e^(-10k)
ln(132/142)=-10k
k=-ln(132/142)/10
k≈0.0073 so
T(t)=68+142e^(-0.0073t) so how long until it reaches 180°?
180=68+142e^(-0.0073t)
112=142e^(-0.0073t)
112/142=e^(-0.0073t)
ln(112/142)=-0.0073t
t= -ln(112/142)/(0.0073)
t≈32.51 minutes
Answer:
SOHCAHTOA.
Step-by-step explanation:
acronym is an abbreviation formed from the initial letters of other words and pronounced as a word
The acronym for sin cosine and tangent is
SOHCAHTOA
Sine =Opposite over Hypotenuse
Cosine= Adjacent over Hypotenuse
Tangent= Opposite over Adjacent
Step-by-step explanation:
We need to find an expression for .
We can solve it as follows.
We know that,
So,
or
Hence, this is the required solution.