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2 years ago

Can you guys please help me

Mathematics

1 answer:

m_a_m_a [10]2 years ago

4 0

The answer is B. First turn all the results from the spelling competition into fractions (or ratios).
Megan: 45/50 = 9/10
Justin: 27/30 = 9/10
Fernando: 84/120 = 7/10
Then, use this information to find which answer is correct.
Have a nice day! :)

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Solve (x – 4)^2=5 Hhhhhbb

Oxana [17]

Answer:

x = 4 + sqrt(5) or x = 4 - sqrt(5)

Step-by-step explanation:

Solve for x:

(x - 4)^2 = 5

Take the square root of both sides:

x - 4 = sqrt(5) or x - 4 = -sqrt(5)

Add 4 to both sides:

x = 4 + sqrt(5) or x - 4 = -sqrt(5)

Add 4 to both sides:

Answer: x = 4 + sqrt(5) or x = 4 - sqrt(5)

6 0

2 years ago

Use the triangle below to find cos V.

Semenov [28]

Answer:

$cos\ V = \frac{2\sqrt{29}}{29}$

Step-by-step explanation:

Given

The attached triangle

Required

Find cos V

In trigonometry:

$cos\theta = \frac{Adjacent}{Hypotenuse}$

In this case:

$cos V= \frac{TV}{UV}$

Where

$TV = 6$

and

$UV^2 = TV^2 + TU^2$ -- Pythagoras

$UV^2 = 6^2 + 15^2$

$UV^2 = 261$

Take square roots

$UV = \sqrt{261$

$UV = \sqrt{9*29$

$UV = \sqrt{9} *\sqrt{29$

$UV = 3\sqrt{29$

So:

$cos V= \frac{TV}{UV}$

$cos\ V = \frac{6}{3\sqrt{29}}$

$cos\ V = \frac{2}{\sqrt{29}}$

Rationalize:

$cos\ V = \frac{2}{\sqrt{29}}*\frac{\sqrt{29}}{\sqrt{29}}$

$cos\ V = \frac{2\sqrt{29}}{29}$

8 0

2 years ago

8 - 4y + (-2y) + 5 What is this answer please tell me

Irina-Kira [14]

Answer:

13 - 6y

Step-by-step explanation:

8 - 4y + (-2y) + 5 = 13 - 6y

8 0

2 years ago

Read 2 more answers

2.4x-9 < 1.8x+6 solve the inequality

nasty-shy [4]

Answer:

x<25

Step-by-step explanation:

Let's solve your inequality step-by-step.

2.4x−9<1.8x+6

Step 1: Subtract 1.8x from both sides.

2.4x−9−1.8x<1.8x+6−1.8x

0.6x−9<6

Step 2: Add 9 to both sides.

0.6x−9+9<6+9

0.6x<15

Step 3: Divide both sides by 0.6

0.6x/0.6 < 15/0.6

x<25

8 0

2 years ago

A baby bird jumps from a tree branch and flutters to the ground. The function "f" models the bird's height (in meters) above the

AURORKA [14]

The answer to this question will depend on the function f itself. Basically you will find the height in meters above the ground of the bird when it jumped when the time t=0s. This is substsitute every t in the function for a value of zero and that way you will get the bird's height at the time it jumped. If you were given a graph for this function, you can find the y-intercept of the graph and that will be the answer as well. The question could be written like this:

A baby bird jumps from a tree branch and flutters to the ground. The function " $f(t)-4.9t^{2}+25$ " models the bird's height (in meters) above the ground as a function of time (in seconds) after jumping. What is bird's height above the ground when it jumped.

Answer:

25m

Step-by-step explanation:

Once your function is given, you can substitute t=0 since 0s is the time measured at the moment the bird jumped. So our function will be:

$f(0)=-4.9(0)^2+25$

$f(0)=25m$

So the height of the bird above the ground when it jumped is 25m in this particular function.

8 0

2 years ago