Answer:
0, BRAINLIEST PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS
Answer:
I believe the answer is number 4
Step-by-step explanation:
p(2 or 4) together is 28 and p(3 or less) together is 43
Answer:
$10.44
Step-by-step explanation:
9(0.16)
1.44
9+1.44
10.44
Hope this helps
Btw I got .16 because in order to get a decimal you move the decimal place two to the left. And in this case the 16 has an imaginary decimal after it. Like so 16. So two to the left. .16
Let the total number of cars = 100
Total of sedan, van and sports cars = 39+33+7 = 79
Number of other cars = 100 - 79 = 21.
Let A be the event of owning a sedan,
B be the event of owning a van and
C be the event of owning a sports car.
D be the event of owning other cars.
Then, 
and
Now,
p(non selection of van) = p(A ∪ C ∪ D)
= p(A) + p(C) + p(D)
= 0.67
The probability of none of the three selections would be a van is:
0.67 × 0.67 × 0.67
= 0.300763
=0.301
Hence, the correct option is (D).
There would be about 5357 bees in the hive.
25•3=75
75÷0.014=5357.14285714
